Stems and cones

A stem coarse enough to cut

Below the 3/5 rung is a 2/3 rung, and it runs from a rise of 0.050 to 0.120. It is not a lattice across all of it: from 0.090 to 0.115 the divergence stops settling and sticks on exactly three eighths of a turn, wobbling by a degree and a half — while a counter goes on reporting 2/3 as though nothing had happened.

Worth reading first: A head is a set of points · Counting the spirals · A pattern with a rate.

A two-organ cut wrecks a stem at the 3/5 rung, where every single removal heals, and what the wrecked stem settles into is the lattice it was cut from wound the other way: the same divergence subtracted from a full turn, the same counted pair, the same order of shortest steps, mirrored. At the 5/8 rung nothing of the kind happens.

The account offered for that difference was reachability. A reflection is not a small change — every organ of the front has to end up somewhere it was not — so a stem falls into its mirror only if the rearrangement is short enough to be carried there. A front of five has fewer arrangements to pass through than a front of eight, so the coarse rung reaches its mirror and the fine one does not.

The wrecked stem is the lattice it was cut from, wound the other wayThe divergence of each organ placed after two were removed from a settled stem at a rise of 0.032, over the 180 organs following the cut. The upper line is the divergence the undisturbed stem holds, 139.6875°; the lower is 220.3125°, which is 360° minus it and therefore the same lattice with the opposite handedness. The sequence is thrown by the cut, wanders for a few dozen organs, and settles on the second line to four decimal places — 220.3125° against 220.3125° — where it stays. A counter shown the positions afterwards returns 3 and 5, the pair the stem was cut from. Nothing about the pattern has been lost; its chirality has been reversed, which at this rung a single removal cannot do.139.688°as grown220.313°its mirror060120organs placed after the cutdivergencerise 0.032 · organs 3 and 6 back removed · counted 3/5generated from a stated rule, not drawn to look right
Fig. 1 The outcome the account is about. A stem cut of two organs, settling into the reflection of the lattice it came from.

That predicts something testable: a 2/3 stem should reverse more readily than a 3/5 one. The rung below 3/5 is coarser than anything this collection has grown, and the obvious hazard was stated when the prediction was: a stem that coarse may not be a lattice at all, and cutting a thing that is not a lattice answers a different question.

This essay establishes what is there before anything is cut. It turns out the hazard was real, it sits in the middle of the rung rather than at its edges, and the instrument that would normally catch it cannot.

Where the coarse rungs are

Grow a stem by the rule at a stated rise, let it settle over four hundred organs, and read two things off it: the mean divergence over the last sixty, and the pair a counter returns when it is shown the positions.

Every transition as the rise fallsThe pair climbs 1/2 → 2/3 → 3/5 → 5/8 → 8/13. Consecutive transitions are 0.381, 0.382, 0.382 of the previous rise — 1/φ² is 0.3820.0.4000.6000.8001-2-1.50-1log₁₀ of the rise between nodes (falling to the right is the plant growing)log₁₀ of the larger parastichy number2/33/55/88/13500 rises, shortest vectors recomputed at eachratio 0.3819 against 1/φ² = 0.3820
Fig. 2 The ladder the rungs sit on. Sweeping the rise, the counted pair holds constant over a range and then steps, and the coarse end of it is where this essay works.

Swept from a rise of 0.040 up to 0.130 in steps of 0.005, the counted pair is 3/5 at the first two, 2/3 from 0.050 to 0.120, and 1/2 from 0.125 upwards. So there is a 2/3 rung, it is nine rises wide at this resolution, and there is a coarser rung below it again.

Which rises are a lattice, from 0.04 to 0.13How much the divergence wanders over the last sixty organs, at each rise up the coarse ladder. 13 of the 19 settle, scattering between 0.0000 and 0.3356 degrees. six do not: from 0.09 to 0.115 the divergence sticks on exactly 135.0000 degrees, which is three eighths of a turn, and wobbles about it by 0.79 to 1.60 degrees. A counter shown either kind returns the same pair, so the counts cannot tell them apart. The line is the threshold a rise has to pass before a cut is made on it, and it sits in the gap rather than among the measurements.0.5°1.5°0.043/53/50.052/32/30.062/32/30.072/32/30.082/32/30.092/32/30.12/32/30.112/32/30.122/31/20.131/2settles: 0.5°rise, and the pair a counter returnshow much the divergence wanders (°)stuck on 135.000° — three eighths of a turn19 rises · 13 a cut may be made ongenerated from a stated rule, not drawn to look right
Fig. 3 The whole coarse ladder. Each bar is how much the divergence wanders over the last sixty organs at that rise, with the pair a counter returns written underneath.
A stem unrolled: 90 nodes at 139.45° with a rise of 0.060 circumferencesThe counter is shown these coordinates and the circumference, and finds 2 parastichies one way and 3 the other. The faint strips left and right are the same stem: a family leaving one edge re-enters at the other.2 and 3rise 0.060 · divergence 139.45°counted 2 and 3, opposed
Fig. 4 What a stem on the 2/3 rung looks like, unrolled. Three organs to a turn and a bit, which is as coarse as an arrangement gets before it stops having two families at all.

The settled divergence slides across the rung the way it does across every rung — and what that slide does to a front is its own question, as is what a coarse enough rung does to the mirror: 140.47° at the coarse end, down through 139.45°, 138.75°, 137.93°, 137.11° and 136.17° to 135.35°, with the counted pair constant across the whole slide. That is the ordinary picture and there is nothing wrong with it.

Two runs of the same rule from unrelated starting anglesBoth settle at 137.5°, within 0.0° of the golden angle, from seeds 166° apart.1301401500100200300stepdivergence angle produced at that step (°)golden anglegrowth 0.50settled spread 0.00°
Fig. 5 What a rung member does, read as a run rather than as a number: a transient, and then a divergence that holds flat to the resolution of the grid.

The band in the middle that does not settle

From a rise of 0.090 to 0.115 it stops.

At those five rises the mean divergence is 135.0000° — to four decimal places, at every one of them — and it does not hold still. The scatter over the last sixty organs runs from 0.79° to 1.60°, where every other rise on the rung scatters between 0.0000° and 0.3356°.

rise mean divergence scatter
0.080 136.1719° 0.0000°
0.085 135.3516° 0.1172°
0.090 135.0000° 1.5982°
0.100 135.0000° 1.5099°
0.115 135.0000° 0.7948°
0.120 135.4688° 0.0000°
Which rises are a lattice, from 0.07 to 0.13How much the divergence wanders over the last sixty organs, at each rise up the coarse ladder. seven of the 13 settle, scattering between 0.0000 and 0.1172 degrees. six do not: from 0.09 to 0.115 the divergence sticks on exactly 135.0000 degrees, which is three eighths of a turn, and wobbles about it by 0.79 to 1.60 degrees. A counter shown either kind returns the same pair, so the counts cannot tell them apart. The line is the threshold a rise has to pass before a cut is made on it, and it sits in the gap rather than among the measurements.0.5°1.5°0.072/32/30.082/32/30.092/32/30.12/32/30.112/32/30.122/31/20.131/2settles: 0.5°rise, and the pair a counter returnshow much the divergence wanders (°)stuck on 135.000° — three eighths of a turn13 rises · 7 a cut may be made ongenerated from a stated rule, not drawn to look right
Fig. 6 The band on its own, at the resolution that shows it. Five bars an order of magnitude taller than their neighbours, and the line is the threshold a rise has to pass before a cut is made on it.

135° is three eighths of a turn. The stem has not settled on a lattice divergence; it has locked on a rational one, and it wobbles about it by more than a degree.

A head of 300 primordia at a divergence of 135.00°Nothing is placed by hand: the nth point sits at n·135.00° and radius √n. The closest any two points come is 0.23 of the mean spacing.divergence 135.000°closest pair 0.23 × mean spacing
Fig. 7 Three eighths of a turn, drawn exactly. Eight files, radial gaps between them, and none of the packing that makes a spiral arrangement worth studying.
How nearly each angle is a simple fraction of a turnA dip means a rational approximation and a lattice with visible rows. The golden angle's floor is 0.008; the rational angle reaches exactly zero.00.2000.400204060denominator qhow nearly q × angle is a whole turn (0 = exactly)golden 137.508°137.3°135° = 3/8distance to the nearest whole turnno dips means no rows
Fig. 8 Where 135 degrees sits among the fractions: a denominator of eight, which is small enough to make files and is nothing like the golden angle’s position.

The rung is real before the band is a problem

Before the band is worth calling a hazard, the rung it sits in has to be shown to be an ordinary rung, or the whole ladder is suspect rather than one part of it.

Four things say it is. The counted pair agrees with the contact geometry at every rise — the counter, shown the positions and told nothing, returns the pair that the two shortest steps say it should. The rung has boundaries in the right places: 3/5 above it and 1/2 below, each replacing the pair one step along the ladder that every other rung on this site follows. The settled divergence slides monotonically across it. And the front, measured by removing one organ at a time and asking which offsets are felt, is three organs deep, which is the larger of the two counts, exactly as at every finer rung.

On a rung the response is a run of offsets; near a transition it has a holeOne row per rise, from 0.06 at the top to 0.013 at the bottom, and one column per offset: the organ one place back at the left, twelve places back at the right. A cell is filled where removing that organ moves the next organ by more than 2.5°, and empty where it does not. On a rung the filled cells are a run from one to the larger parastichy number — 3, 5, 8 at the pairs shown on the left. Every rise shown here is in the middle of its rung, so every row is a run and nothing past it is felt — what happens between the rungs is a separate matter.riseorgans back from the tip →run · isolated246810120.062/330.0323/550.0135/883 rises · 1536 azimuthsgenerated from a stated rule, not drawn to look right
Fig. 9 The front at the coarse rung beside two finer ones. Three organs, which is the larger of its two counts, and the same rule holds at all three.
The same rule, the same rise, two lattices, two frontsHow many organs back a single removal is still felt, on a stem seeded onto the golden lattice and on one seeded onto the Lucas lattice, at seven rises. Everything but the seed is identical at each rise — the rule, the spacing, the heights, the azimuth grid — and the two fronts differ at every one of them. Which branch has the wider front changes hands four times going down the range, so no function of the rise gives the column. The golden branch carries 5/8 at four of these rises, across a factor of two in the rise, and its front is eight at all four.456781011121.621.701.801.8922.102.22rise (falling to the right)how deep the front is, in organs3/53/44/75/87/118/13goldenLucas7 rises · both branches settled to under 0.5°4 reversals
Fig. 10 And the same measurement made a second way across seven finer rises, on stems grown from a stated seed, so that the front is not being read off a single run.

So the coarse rung is a rung. What sits in the middle of it is not a failure of the ladder; it is a state the rule can occupy that the ladder has no row for.

The counter cannot see it

This is the part that makes the band a hazard rather than a curiosity.

A counter shown a locked stem returns 2/3 — the same pair as every other rise on the rung. It is not confused and it is not wrong. Three eighths of a turn is close enough to the rung’s own divergences that the two shortest chains of near neighbours are still the same two, and the wobble is large enough that the eight files three eighths would make never quite form.

The spiral counts four different divergence angles produceFibonacci counts come from one angle. The Lucas angle — which the same dynamical model reaches on a different branch — gives 47 and 76, and neither number is a Fibonacci number.golden 137.51°55 and 89FibonacciLucas 99.50°47 and 76Lucas151.14°50 and 81neither77.96°37 and 60neithercounted from the pointsone sequence per branch
Fig. 11 Why the counter reports what it does: the pair it returns as the divergence is swept changes at boundaries, and 135 degrees is not near one of them at this rise.
What a divergence picked at random gives, at a rise of 0.100Fibonacci pairs take 59.6% of the circle at this rise, and the share falls as the rise does. The claim that Fibonacci counts are what nature "prefers" needs the preference to come from somewhere, and it is not from the geometry being generous.Fibonacci59.6%Lucas20.8%whorled10.7%other8.9%5 distinct pairs over 1200 divergencesrise 0.100Fibonacci 59.6%
Fig. 12 The counter run across the band itself, reporting the rung’s pair at every rise in it. Nothing in the counted output marks these rises as different.

So every instrument that decides what a stem is by counting it says the band is ordinary 2/3. The only measurement that separates it is the one nobody thinks to make: how much the divergence moves once it has stopped moving.

Two runs of the same rule from unrelated starting anglesBoth settle at 137.0°, within 0.5° of the golden angle, from seeds 166° apart.1201301401500100200300400stepdivergence angle produced at that step (°)golden anglegrowth 0.40settled spread 0.00°
Fig. 13 The measurement in question, on a stem that does settle. The transient dies and the divergence goes flat, which is what “settled” is being asked to mean.
A lattice survives about 1.7° of scatter, whichever way the noise arrivesThe largest divergence scatter at which a run is still a lattice, from each kind of noise at the largest amplitude that leaves one. The two routes share no code below the placement rule: one displaces the node after the choice, the other perturbs the energy the choice is made over. They agree to 0.55°.placement noise, at 1°1.97°field noise, at 0.015 of the barrier1.42°no noise at all0.64°largest divergence scatter still holding a latticethe two differ by 0.55° — a fifth of what either toleratesand by 2.6× more than a noiseless run scatters65 nodes per rung · 4 runs per amplitude1.97° against 1.42°
Fig. 14 And the general form of the caution: a tolerance stated loosely enough will admit a stem that is still moving, and the admitted rows then look like ordinary rows.

Two things a locked stem still does

It is worth recording what does not break in the band, because “not a lattice” is a strong phrase and the object is more specific than that.

A locked stem still packs. Its organs are placed by the same rule at the same prescribed heights, they do not collide, and a counter finds two families in them. It is not disordered, and none of the disorder statistics this collection uses reports anything unusual about it.

The same stem, not unrolled50 of the 100 nodes face the reader and 50 are behind the stem, drawn open. The count is 2 and 3 either way; the unrolling changes nothing but the visibility.near facefar face100 nodes at 135.00°2 and 3, both faces
Fig. 15 A locked stem in the round. Regular, non-colliding, two families, and no divergence.

And it still repeats, after a fashion. Three eighths of a turn brings the pattern back to itself every eight organs, so the neighbourhood an organ is placed into is nearly periodic. That is what makes the state stable at all — the rule is sitting in a landscape that repeats, rather than being pushed around at random.

The disorder of a head against its divergence angle, 300 pointsμ₂ is the mean squared departure of a Voronoi cell's side count from six, measured on 300 points inside 86% of the radius. Swept across 1.60° it is a staircase: flat over stretches of a few hundredths of a degree, with sharp steps between them and narrow deep dips wherever a rational falls. At 137.144° — which is 360 × 8/21 — it is 0.078; At 137.648° — which is 360 × 13/34 — it is 0.197; At 138.460° — which is 360 × 5/13 — it is 0.060. The ticks along the top are the fractions p/q, placed from arithmetic rather than from the curve.00.2000.4000.600137138138139divergence angle, degreesμ₂, the mean squared departure of a cell's side count from six5/138/2113/34401 angles · 0.0040° apart · 300 points eachmarks are the fractions, placed from arithmetic
Fig. 16 The statistic that would have caught genuine disorder, swept across a stretch of the divergence where the rule is well behaved. It reports nothing unusual about the locked band either: a stem stuck on a rational is not disordered.

What it does not do is hold a single divergence, which is the one property every claim in this thread is stated over. A cut is made against a control, the control’s settled value is the reference, and a stem with no settled value has no reference to be compared against.

A round trip on four heads of 900 primordia: the divergence angle recovered from eachThe counter is shown the points and nothing else. The worst recovery across the four is 0.012°.the first of the four — 225 of its 899 pointsused to buildcountsrecovered137.508°55 · 89137.520°99.502°47 · 7699.500°151.100°31 · 81151.105°77.960°37 · 6077.960°worst error 0.012°counts in, angle outthe recovery never sees the angle
Fig. 17 Why the reference matters: every claim about what a cut did is a difference from what the undisturbed stem was doing, and that requires the undisturbed stem to be doing one thing.

The threshold, and where it sits

A rise is admitted to the sweep if its divergence scatters by no more than half a degree and its counted pair agrees with its contact geometry.

Half a degree is not a delicate number here. The rises that settle scatter by at most 0.3356° and the rises that do not scatter by at least 0.7948°, so any threshold between those two sorts the ladder identically. The gap is four tenths of a degree wide and the threshold sits in the middle of it.

Which rises are a lattice, from 0.045 to 0.125How much the divergence wanders over the last sixty organs, at each rise up the coarse ladder. eleven of the 17 settle, scattering between 0.0000 and 0.3356 degrees. six do not: from 0.09 to 0.115 the divergence sticks on exactly 135.0000 degrees, which is three eighths of a turn, and wobbles about it by 0.79 to 1.60 degrees. A counter shown either kind returns the same pair, so the counts cannot tell them apart. The line is the threshold a rise has to pass before a cut is made on it, and it sits in the gap rather than among the measurements.0.5°1.5°0.0453/52/30.0552/32/30.0652/32/30.0752/32/30.0852/32/30.0952/32/30.1052/32/30.1152/32/30.1251/2settles: 0.5°rise, and the pair a counter returnshow much the divergence wanders (°)stuck on 135.000° — three eighths of a turn17 rises · 11 a cut may be made ongenerated from a stated rule, not drawn to look right
Fig. 18 The gap, drawn. Nine bars below the line and six well above it, with nothing in between.

That matters because the whole point of the test is that it rejects something. A test written after the rows were chosen would have admitted everything; this one throws out five of the nine rises in the middle of the rung, which is a third of the ladder and includes the rises a sweep by round numbers would have picked first.

A lattice or a wreck, with nothing in betweenEvery run in the sweep, at both kinds of noise. The line at 6° is where a run stops being counted as a lattice, and nothing lands near it: the intact runs reach 1.97° and the destroyed ones start at 8.06°, a factor of 4.1 away.00.50011.5001234567amplitude, by stepscatter, log₁₀ degreesintactno latticeplacementfield64 runs · both kindsan empty factor of 4.1 at the cut
Fig. 19 Why a scatter measurement is the right instrument for this: it is the quantity that separates a lattice from a stem still being pushed around, and it is sensitive well below the resolution of a count.

Why nobody would have noticed

The band is invisible to four of the five things anybody would check, and going through them is the point of the essay.

The counted pair says 2/3 across the whole rung, band included. The front, measured by removing one organ and asking which offsets are felt, is three organs deep across the whole rung. The mean divergence at 135.0000° sits between the values at 0.085 and 0.120 and is exactly where a smooth slide would put it — it is not an outlier on the curve. And a drawing of a locked stem looks like a drawing of a coarse stem, because a wobble of a degree and a half at a spacing of a hundred and twenty degrees is not something an eye picks up.

A stem unrolled: 120 nodes at 135.00° with a rise of 0.100 circumferencesThe counter is shown these coordinates and the circumference, and finds 2 parastichies one way and 3 the other. The faint strips left and right are the same stem: a family leaving one edge re-enters at the other.2 and 3rise 0.100 · divergence 135.00°counted 2 and 3, opposed
Fig. 20 A locked stem, unrolled. It looks like an ordinary coarse arrangement, because at this spacing a wobble of a degree and a half is not visible.
A stem unrolled: 120 nodes at 136.17° with a rise of 0.080 circumferencesThe counter is shown these coordinates and the circumference, and finds 2 parastichies one way and 3 the other. The faint strips left and right are the same stem: a family leaving one edge re-enters at the other.2 and 3rise 0.080 · divergence 136.17°counted 2 and 3, opposed
Fig. 21 And a settled one at a neighbouring rise, for the comparison. The difference between these two is a number rather than a picture.

The fifth thing does see it, and it is the one this collection has been in the habit of measuring since the collection began: how much the divergence moves once the transient is over. That is not a check anybody runs to decide whether a stem is a lattice; it is a check run to decide whether a run is long enough. It happens to be the only instrument here that separates the band from the rung.

Which rises are a lattice, from 0.085 to 0.12How much the divergence wanders over the last sixty organs, at each rise up the coarse ladder. two of the eight settle, scattering between 0.0000 and 0.1172 degrees. six do not: from 0.09 to 0.115 the divergence sticks on exactly 135.0000 degrees, which is three eighths of a turn, and wobbles about it by 0.79 to 1.60 degrees. A counter shown either kind returns the same pair, so the counts cannot tell them apart. The line is the threshold a rise has to pass before a cut is made on it, and it sits in the gap rather than among the measurements.0.5°1.5°0.0852/32/30.0952/32/30.1052/32/30.1152/32/3settles: 0.5°rise, and the pair a counter returnshow much the divergence wanders (°)stuck on 135.000° — three eighths of a turn8 rises · 2 a cut may be made ongenerated from a stated rule, not drawn to look right
Fig. 22 The one measurement that sees it, on the rises that matter: how much the divergence of each stem is still moving once its transient is over.
Two runs of the same rule from unrelated starting anglesBoth settle at 137.0°, within 0.5° of the golden angle, from seeds 166° apart.1201301401500100200stepdivergence angle produced at that step (°)golden anglegrowth 0.40settled spread 0.00°
Fig. 23 And what settling looks like when it happens, which is the shape the band never reaches.

That is the shape of a defect worth recording. Not a wrong number produced by a broken instrument, but a state that every instrument reports correctly and that nobody would think to ask about.

What the band probably is

Not the subject of this essay, and worth a paragraph because leaving it unnamed would suggest it is unexplained.

Three eighths of a turn is a rational divergence with a small denominator, and a rational divergence is a fixed point of a different kind: the pattern repeats exactly every eight organs, so an organ placed at the argmin of the profile has a perfectly periodic landscape to sit in. The rule can hold that, and at rises where the true lattice divergence passes near it the rule apparently prefers it — but holding it exactly would require the wobble to vanish, and it does not.

The gaps close faster than the dips narrowFor each Fibonacci fraction, the distance to the nearest other rational with a denominator of 60 or less, and the half-width of its own dip at the smallest head that resolves it. The gaps fall from 0.763° at 3/8 to 0.0735° at 34/89; the dips stay between 0.0077° and 0.0155°. The dips never touch — the closest they come is a factor of 10 — so what stops the measurement is not the dips overlapping but the background between them ceasing to be flat. The clear offsets available fall from 72 to 53.-2-1.50-1-0.5000divergence angle, as a fraction of a turndegrees (logarithmic)3/85/138/2113/3421/5534/89to the nearest other rationalthe dip's own half-widthsix denominatorsgenerated from a stated rule, not drawn to look right
Fig. 24 The general fact behind that: rationals with small denominators are the places a pattern can repeat exactly, and they are sparse and strong.
Placements that went to a different minimum, per thousandThe rule's own counterfactual, run beside it: where would this node have gone with the noise taken away and everything else left alone? Placement noise displaces the node after the argmin, so the answer is always "here" — 0.2°, 0.4°, 0.8° all give zero. A jostle and a field perturbation are upstream of the choice and change one or two placements in a thousand while the lattice is still intact.field 0.0052.10.70° of scatterfield 0.00750.01.00° of scatterfield 0.010.01.12° of scatterjostle 0.22.10.89° of scatterjostle 0.41.10.87° of scatterjostle 0.81.11.12° of scatterplacement 0.20.00.78° of scatterplacement 0.40.00.94° of scatterplacement 0.80.01.42° of scatter3 runs each · a basin change is half a local spacingplacement noise: zero by construction
Fig. 25 And the general behaviour: which state a rule settles into is a matter of basins, and a state can be reachable, stable and not a lattice all at once.

What the band costs the experiment

Five rises of nine is a third of the rung, and the ones lost are in the middle, which is where a sweep would naturally have been made.

A sweep at three round rises — 0.05, 0.10 and 0.15 — would have taken one member of the rung, one member of the band and one member of the rung below. Two of those three rows would have been about something other than a 2/3 lattice, and the table would have shown it as a 2/3 lattice, because the counter says so at all three.

Which rises are a lattice, from 0.05 to 0.15How much the divergence wanders over the last sixty organs, at each rise up the coarse ladder. eleven of the 17 settle, scattering between 0.0000 and 0.3356 degrees. six do not: from 0.09 to 0.115 the divergence sticks on exactly 135.0000 degrees, which is three eighths of a turn, and wobbles about it by 0.79 to 1.60 degrees. A counter shown either kind returns the same pair, so the counts cannot tell them apart. The line is the threshold a rise has to pass before a cut is made on it, and it sits in the gap rather than among the measurements.0.5°1.5°0.052/32/30.062/32/30.072/32/30.082/32/30.092/32/30.12/32/30.112/32/30.122/31/20.131/2settles: 0.5°rise, and the pair a counter returnshow much the divergence wanders (°)stuck on 135.000° — three eighths of a turn17 rises · 11 a cut may be made ongenerated from a stated rule, not drawn to look right
Fig. 26 The three rises a round-number sweep would have chosen, and what is actually at each of them.

That is not hypothetical caution. The result the coarse rung is being cut to test is a share — how often a two-organ cut reverses a stem — and a share computed over thirty-six arrangements at each of three rises is a share over a hundred and eight cells, two thirds of which would have been cells of a stem that had no divergence to reverse.

A second cut moves the next organ, and does not move the boundaryEvery pair of organs that can be taken out of a settled stem at a rise of 0.032, where the pattern is 3/5. A row is the offset of the nearer organ removed, counted back from the tip; a column is how many further places back the second one sits. The shade is how far the next organ ends up from where it would have been, from under a degree in the palest cells to a half-turn in the darkest. The run of shaded rows ends at 5, which is the larger parastichy number, and every row below it is blank across the whole width — the largest displacement anywhere past the front is 2.34°. So the nearer of the two organs decides whether the removal is felt at all, and the second one, wherever it is put, cannot make the pattern notice an organ it was not going to notice.816117891311411391411403811542808477817779441950414244414442915014714915014914914914981079989880210111110121111112121221210000000005 = 5123456789123456789nearer organ,places backgap to the second organ, in placesdisplacement of the next organ, in degrees · pair 3/5rise 0.032 · 400 organs before the cutgenerated from a stated rule, not drawn to look right
Fig. 27 The shape of the table such a sweep produces, drawn at a rise that is a lattice. Run on a stem from the locked band instead, every cell of it would be answering a different question.
Which rises are a lattice, from 0.085 to 0.125How much the divergence wanders over the last sixty organs, at each rise up the coarse ladder. three of the nine settle, scattering between 0.0000 and 0.1172 degrees. six do not: from 0.09 to 0.115 the divergence sticks on exactly 135.0000 degrees, which is three eighths of a turn, and wobbles about it by 0.79 to 1.60 degrees. A counter shown either kind returns the same pair, so the counts cannot tell them apart. The line is the threshold a rise has to pass before a cut is made on it, and it sits in the gap rather than among the measurements.0.5°1.5°0.0852/32/30.0952/32/30.1052/32/30.1152/32/30.1251/2settles: 0.5°rise, and the pair a counter returnshow much the divergence wanders (°)stuck on 135.000° — three eighths of a turn9 rises · 3 a cut may be made ongenerated from a stated rule, not drawn to look right
Fig. 28 The band at the resolution that finds it, which is a step of 0.005 rather than 0.05. A coarser sweep of the rise cannot see this at all.

What the test costs, then, is a factor of ten in the resolution of the rise sweep and a stated criterion. What it buys is a table whose rows are all about the same object.

What is now permitted

Nine rises of the 2/3 rung, from 0.050 to 0.085 and at 0.120, each a settled lattice by a stated test, each counted at the pair its contact geometry gives, and each therefore a legitimate thing to remove two organs from.

Move the second organ far enough back and the experiment is the old oneThe displacement of the next organ when two organs are removed — one one place back and one a further gap behind it — against that gap, at a rise of 0.032 where the pattern is 3/5. The dashed line is what removing the single organ one place back does on its own, computed by the earlier one-organ intervention and not by this one. Inside the front the two vacancies interact and the answer swings over 168°; from the gap that puts the second organ 2 places behind the front onwards it settles onto the single cut's -139.7°, within 0.2°. That limit is what makes the second parameter a control rather than a confound.-180°-90°90°180°one organ-139.7°second organ leaves the front13579gap between the two organs removed, in placesrise 0.032 · nearer organ 1 back · pair 3/5generated from a stated rule, not drawn to look right
Fig. 29 And what the second axis of that table means, drawn at a finer rung where the front is deep enough for the gap to have somewhere to go: moving the second removal through the profile the first one deformed, which is why a two-organ cut is not two one-organ cuts.

That is a smaller ladder than the rung, and the difference is the essay. The prediction under test — that a shallower front reverses more readily — is worth nothing measured on stems that were never lattices, and the rows it would have been measured on are the ones a sweep at 0.09, 0.10 and 0.11 would have chosen.

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