Stems and cones

A wall and not a budget

Below a rise of about 0.005 this collection's stems stop settling onto a lattice, and the limit has been written up four times without anybody asking which kind of limit it is. Grown three times as long, the table is identical row for row: not one stem that failed to settle succeeds. The floor is a wall.

Worth reading first: How long a stem takes to settle · A head is a set of points · Counting the spirals.

Four essays in this collection have said the same thing in passing. Below a rise of about 0.004 or 0.005, a stem does not settle into a countable lattice; the counter comes back with pairs like 2/13 and 11/22 that are not contact families at all; so every sweep that climbs the ladder stops there.

It has been written up as a limit each time, and not once has anybody asked which kind of limit it is. If a stem at 0.003 simply needs longer, the floor is a budget and a longer run buys the next rung down. If it never settles however long it is grown, the floor is a wall and no budget reaches past it. The two have completely different consequences and the distinction costs one extra table.

The same table, grown 2.7 times as long. Every rise and every starting angle, grown to 1200 organs and then to 3200. The two middle columns are how many starting angles reached a lattice at each length, and they are the same column: of the 72 pairs of runs, 72 are identical organ for organ and 0 settle at the longer length after failing at the shorter one. Tripling the budget buys nothing anywhere. What the fine rises are short of is not run length: the share of starting angles that reach a lattice at all falls from 7 of 9 to 1, so the arrangements a stem could fall into have mostly stopped existing.
Fig. 1 The whole answer: the same runs at two lengths, side by side.

The test

Every rise and every starting angle, grown to 1,200 organs and then to 3,200 — nearly three times as long — with the settling measured the same way both times. Seventy-two pairs of runs.

All seventy-two agree exactly. The same stems settle, at the same organ, on the same divergence. Not one stem that failed at 1,200 succeeds at 3,200.

How many organs a stem needs before it is on a lattice. One row per rise, one mark per starting angle, placed at the organ from which every later divergence stays within a degree and a half of the run's own final value. Where a stem settles at all it does so between 0 and 290 organs in, against the 400 every ablation run here grows before it cuts anything. Not one row needs the length it is given. What changes down the table is the count on the right: how many of the nine starting angles reach a lattice at all, which falls from 7 at the coarse rises to 1 at the finest.
Fig. 2 The table at the shorter length.
How many organs a stem needs before it is on a lattice. One row per rise, one mark per starting angle, placed at the organ from which every later divergence stays within a degree and a half of the run's own final value. Where a stem settles at all it does so between 0 and 290 organs in, against the 400 every ablation run here grows before it cuts anything. Not one row needs the length it is given. What changes down the table is the count on the right: how many of the nine starting angles reach a lattice at all, which falls from 7 at the coarse rises to 1 at the finest.
Fig. 3 And at the longer one, which is the same table.

Tripling the budget buys nothing anywhere — not at the fine rises where the question was asked, and not at the coarse ones either.

Three thousand two hundred was chosen rather than a larger number for a reason worth stating. It is eight times the four hundred organs an ablation run grows before it cuts anything and three and a half times the nine hundred a noise run carries, so it covers the range of run lengths any experiment here might plausibly be extended to. A number chosen to be very much larger — fifty thousand, say — would test a different question, which is whether the rule ever settles rather than whether this collection’s budgets were the binding constraint.

Why “identical” is the strong form

It would have been enough for the answer to be nearly the same: a couple of extra runs settling at the longer length, at organ two thousand, would have said the floor was a budget with a steep price. That is not what happened.

The runs are deterministic, so identical rows are not surprising in themselves — the first 1,200 organs of a 3,200-organ run are the same 1,200 organs. What is informative is that the extra two thousand organs contain no settling at all. A run that has not settled by organ 1,200 does not settle by organ 3,200, in any of the forty-odd cases available to check.

The same table, grown 2.7 times as long. Every rise and every starting angle, grown to 1200 organs and then to 3200. The two middle columns are how many starting angles reached a lattice at each length, and they are the same column: of the 72 pairs of runs, 72 are identical organ for organ and 0 settle at the longer length after failing at the shorter one. Tripling the budget buys nothing anywhere. What the fine rises are short of is not run length: the share of starting angles that reach a lattice at all falls from 7 of 9 to 1, so the arrangements a stem could fall into have mostly stopped existing.
Fig. 4 The comparison as a count: how many settle at each length, at each rise.

And the runs that do settle settle earlywithin 290 organs and mostly inside fifty. So the distribution is not a long tail that a longer run would sample further into. It is bimodal: fast, or never.

How many starting angles reach a lattice at all. The share of nine starting angles, spread from 40 to 180 degrees, whose stem settles onto a lattice at each rise. It falls from 7 of 9 at the coarse rises to 1 at the finest, and the runs that fail do not fail by running out of organs — grown three times as long they fail identically. So what closes at the fine end is the set of arrangements a stem can fall into rather than the time it has to find one, which is a different kind of limit and a more interesting one.
Fig. 5 The other half of the same table: how many starting angles reach a lattice at all, which is what does change with the rise.

The forty-odd cases the claim rests on

A null result over seventy-two pairs sounds larger than it is, so it is worth counting what actually bears on the question.

Of the seventy-two, thirty-one settle at both lengths and forty-one settle at neither. The thirty-one carry no information about budgets — they had arrived before the shorter run ended — so the claim rests on the forty-one that never arrive. Every one of those had two thousand extra organs at the longer length and used none of them.

The same table, grown 2.7 times as long. Every rise and every starting angle, grown to 1200 organs and then to 3200. The two middle columns are how many starting angles reached a lattice at each length, and they are the same column: of the 72 pairs of runs, 72 are identical organ for organ and 0 settle at the longer length after failing at the shorter one. Tripling the budget buys nothing anywhere. What the fine rises are short of is not run length: the share of starting angles that reach a lattice at all falls from 7 of 9 to 1, so the arrangements a stem could fall into have mostly stopped existing.
Fig. 6 The table with the two columns that matter: how many settle at each length, which are the same numbers.

Forty-one is a decent number and it is spread across all eight rises, which is what makes it more than a statement about the fine end. Even at a rise of 0.030, where seven of nine settle quickly, the two that do not are not slow — they are still not settled after three thousand organs.

How many organs a stem needs before it is on a lattice. One row per rise, one mark per starting angle, placed at the organ from which every later divergence stays within a degree and a half of the run's own final value. Where a stem settles at all it does so between 0 and 290 organs in, against the 400 every ablation run here grows before it cuts anything. Not one row needs the length it is given. What changes down the table is the count on the right: how many of the nine starting angles reach a lattice at all, which falls from 7 at the coarse rises to 1 at the finest.
Fig. 7 The coarse rows, where the failures sit beside settlings of eight and ten organs.

That is the detail that turns the result from a fact about fine rises into a fact about the rule. A failure to settle is not a matter of degree anywhere on the ladder: at every rise, a run either arrives quickly or does not arrive.

What is actually falling

Not the speed. The share.

Seven of nine starting angles settle at a rise of 0.030. Seven at 0.013. Five at 0.008. Three at 0.005. And one at each of 0.0045, 0.004 and 0.003.

How many starting angles reach a lattice at all. The share of nine starting angles, spread from 40 to 180 degrees, whose stem settles onto a lattice at each rise. It falls from 7 of 9 at the coarse rises to 1 at the finest, and the runs that fail do not fail by running out of organs — grown three times as long they fail identically. So what closes at the fine end is the set of arrangements a stem can fall into rather than the time it has to find one, which is a different kind of limit and a more interesting one.
Fig. 8 The share falling down the table, measured at the shorter length and identical at the longer.

So the fine end is not a place where stems take longer to arrive. It is a place where there is progressively less to arrive at. The arrangements a starting angle can fall into have mostly stopped existing, and the honest description of the floor is that the basin closes, not that the clock runs out.

That is a considerably more interesting statement than the one it replaces, and it has a check in it: the single survivor at 0.004 settles on 106.1° and the one at 0.003 on 151.3°, neither of which is a divergence any branch of this ladder reaches. Even the stems that do settle down there are not settling onto the lattices the ladder is made of.

six limit divergences, all of them 137.5078 over a whole number. The golden angle is the k = 1 member of a family. Real bijugate plants — teasel, Cephalaria — are reported near 68.75°, which is exactly half of it, and the pairs they are counted at are the Fibonacci pairs doubled.
Fig. 9 The angles the branches reach, which the fine-end survivors are not near.

Which agrees with the ladder itself

The ladder was swept independently, for a different purpose, and it says the same thing from the other side.

Sweeping the rise at one per cent and reading the counted pair, the golden branch carries rungs down to about 0.0048 and the Lucas branch to about 0.0057. Below those the sweep still returns pairs — 2/4, 8/16, 3/11, 11/13 — at settled divergences of 129° to 226°, which neither branch goes anywhere near.

The golden ladder, rung by rung. Each bar is one rung — a run of rises over which a counter returns one pair — drawn from its coarse end on the left to its fine end on the right, with the whole bar scaled to the same width so that positions inside different rungs can be compared. The mark on each bar is the rise at which the two contact steps change places, and it falls between 12 and 35 per cent of the way down on every rung that has one. The dots are the lattices this collection's ablation census was grown at, dropped onto the rungs they belong to. They are not spread across the bars; seven of them sit past the mark.
Fig. 10 The golden ladder, whose finest rung ends where the settling table’s share collapses.

Those are not rungs, and they are excluded from the ladder on the divergence rather than on whether a pair came back — because a pair always comes back. The two measurements were made for unrelated reasons and they put the end of the ladder in the same place.

Every transition as the rise falls. The pair climbs 1/2 → 2/3 → 3/5 → 5/8 → 8/13. Consecutive transitions are 0.381, 0.382, 0.382 of the previous rise — 1/φ² is 0.3820.
Fig. 11 The ladder as the collection has always drawn it, whose bottom is now measured twice.
The Lucas ladder, rung by rung. Each bar is one rung — a run of rises over which a counter returns one pair — drawn from its coarse end on the left to its fine end on the right, with the whole bar scaled to the same width so that positions inside different rungs can be compared. The mark on each bar is the rise at which the two contact steps change places, and it falls between 6 and 40 per cent of the way down on every rung that has one. The dots are the lattices this collection's ablation census was grown at, dropped onto the rungs they belong to. They are not spread across the bars; three of them sit past the mark.
Fig. 12 And the Lucas branch, whose own floor sits a little higher.

What a wall means for the collection

Three things, and the first is a relief.

Nothing here was cut short. Every sweep that stopped at 0.005 stopped at a real boundary rather than at a budget somebody chose. The bounds written into four essays are honest bounds and none of them needs re-running longer.

The 3/5 rung at a tenth of the ladder's step. Every rise of one rung, sampled ten times as finely as the ladder that found the locked band. All 23 are counted at 3 and 5 spirals and all 23 settle: the largest wander is 0.221 degrees, against the 0.5 degree threshold and against the 0.79 to 1.60 degrees the band on the coarse rung wobbles by. The divergence slides smoothly from 139.0625 to 136.7344 degrees with no rise stuck on a rational and none stuck on anything else. Whatever the band is, it is not something a coarser sampling was hiding here.
Fig. 13 One of the sweeps that stopped there, which stopped for the right reason.

The subject has an end. The Fibonacci ladder is usually described as infinite: rung after rung, 3/5, 5/8, 8/13, 13/21, converging on the golden angle as the rise falls to nothing. Under this rule, on these runs, it does not go on forever. The rungs stop at 8/13 on one branch and 7/11 on the other, and below that the rule produces arrangements that are not lattices at all.

The plane of stems: divergence across, rise up. Each shade is one parastichy pair. The marked points are the lattices where three families are equally short — the forks — and the Fibonacci ones run up the middle towards 137.51°.
Fig. 14 The classical diagram, which continues indefinitely, against a rule that does not.

That is a statement about the rule rather than about plants, and the distinction matters: the diagram continues because it is a statement about which lattices exist, and a lattice exists at every rise. What stops is the rule’s ability to find one.

Where this implementation stops converging. Below about G = 0.18 the settled angle wanders over 113° however long the run. That is the model's limit, not a fact about plants.
Fig. 15 Another place this collection has drawn the boundary of a model rather than of a subject.

And it explains a shape nobody had explained. The share of starting angles that settle falls smoothly from seven of nine to one of nine across a factor of ten in the rise. A wall with a sharp edge would fall from seven to zero at one rise. This one narrows.

How many starting angles reach a lattice at all. The share of nine starting angles, spread from 40 to 180 degrees, whose stem settles onto a lattice at each rise. It falls from 7 of 9 at the coarse rises to 1 at the finest, and the runs that fail do not fail by running out of organs — grown three times as long they fail identically. So what closes at the fine end is the set of arrangements a stem can fall into rather than the time it has to find one, which is a different kind of limit and a more interesting one.
Fig. 16 The narrowing, which is a gradual property and not the step a hard limit would produce.

Why the basin narrows

The obvious account is the front. As the rise falls, the number of organs a new one is placed against grows — the contact numbers climb the ladder — so the rule is minimising a sum with more terms in it, over a more crowded neighbourhood.

How many offsets wreck, along the 5/8 rung. The count of offsets that never repair, at each rise on one rung. It runs from 1 at the coarse end to 5 at the fine end, while a counter returns 5 and 8 spirals at every one of them. The front — the run of recent organs at which a removal is felt at all — deepens as the rise falls, so there are simply more places a cut can land and fail to heal. That is the mechanism under the grid: the offsets that appear at the fine end are the ones beyond the smaller contact number, and those are the ones that keep the larger family.
Fig. 17 The front deepening as the rise falls, which is the quantity the account rests on.

A sum with more terms has more local minima, and a starting angle that is not close to a good one has more places to get stuck. That predicts what is seen: not a boundary but a narrowing, with the surviving basins getting smaller as the neighbourhood gets deeper. It also fits what the ablation thread finds from the other direction, where a deeper front makes more offsets wreck: the same crowding that gives a cut more places to do permanent damage gives a starting angle more places to get stuck.

It also predicts something not measured here, which is the right way for an account to be stated. Runs that fail should fail by sticking — settling onto something that is not a lattice — rather than by wandering forever. Whether the failures are stuck or wandering is a distinction the settling test does not draw, because it reports only that the tail is not steady.

The disturbance with the largest wander leaves none in the sequence. How much of a divergence sequence's variance survives being averaged over blocks, on kinematic lattices. The vertical quantity is B² times the variance of the block means divided by the variance of the sequence, which is one at every block size for independent errors — the arithmetic is normalised for a differenced stream, since a divergence is the difference of two organs' errors. A line that climbs is a sequence with power at frequencies below one per block. The disturbances that remember the last error climb to 32 at a block of 128. The ones inherited between touching organs do not climb at all — 1.06 and 0.83 at the same block — although their own deviates carry ×5 and ×49 an independent stream's variance in exactly this statistic. What they do instead is dig a hole: at block sizes of 8 and 13, which are the offsets they couple at, the statistic falls to 0.22 and 0.21.
Fig. 18 The quantity that would draw the distinction, which this table does not read.

Reading it against the four earlier statements

The four essays that named the floor said slightly different things, and the measurement resolves them differently.

The version that said stems below about 0.004 do not settle into a countable lattice at any affordable length is now exactly right, with “affordable” removable: they do not settle at any length tried, and the lengths tried are three times what any experiment here uses.

The version that said the counter returns pairs like 2/13 that are not contact families is right and is now explained. Those pairs come from arrangements that have not settled, and a counter shown an unsettled arrangement returns something rather than nothing, which is the property that made the floor easy to miss.

The two spiral families a counter finds between 0.43 and 0.67 of the radius. 21 spirals one way and 34 the other, found from the point positions alone — the counter is never told the divergence angle.
Fig. 19 The counter, which answers whatever it is shown and does not report that an arrangement is unsettled.

The version that treated the floor as a bound on the contact-scale sweep — three rises rather than the wider span the question wanted — is right and cannot be improved by patience. That sweep’s span of contact scales is a factor of four rather than the eleven it was posed with, and it stays that way.

The deeper rule against the disturbance's memory, at three contact scales. How many of six seeds agree that the deeper rule passed more drift, swept across the correlation length of the disturbance, at three rises. The rule, the amplitude and the run length are identical in every panel; only the rise differs, and with it the contact numbers — 3 and 5, then 5 and 8, then 8 and 13. The shapes are not the same: 3/5 is crossing, 5/8 is no corner, 8/13 is crossing. A corner that sat at a fixed number of organs would look the same in all three, and it does not.
Fig. 20 The sweep that was bounded by the floor, whose span is fixed by it rather than by effort.

And the version that read the floor as a reason the ladder’s fine end is unexplored needs its emphasis moved. It is not unexplored. It is empty of the thing that would be explored.

What would change the answer

A different rule. Everything here is the placement rule at its standard exponent and reach, and the wall is a property of that rule. A rule with a shallower falloff reads fewer organs and might find the fine lattices where this one does not.

A rule too long-ranged makes no pattern; every shorter one makes the same pattern. Each dot is 4 runs from a coarse start at one exponent, separated by 0.2° of placement noise. Below p ≈ 1.1 the divergence scatters by tens of degrees, which is what an arbitrary sequence gives. From p = 1.25 to p = 8 — a sixfold range — every run ends on 8/13 with the scatter between 0.75° and 1.06°.
Fig. 21 The exponent the wall might depend on, swept elsewhere for a different question.

That is a one-table experiment and it is worth doing, because it bears directly on whether the wall is about the geometry or about the rule. If every exponent walls at the same rise, the fine lattices are unreachable in a way that suggests something about them; if the wall moves, it is a fact about a parameter.

There is a reason to expect it to move, which makes the experiment more than box-ticking. The account above says the basin narrows because the neighbourhood deepens, and the exponent is the parameter that sets the depth — a shallower falloff reads dozens of organs where a steeper one reads a handful. If the account is right, a steep rule should wall lower down the ladder than a shallow one, and the wall’s position should track the depth rather than the rise.

A different starting procedure would also change it. Every run here starts from a seed of eight organs at a stated angle and grows. A run started from a lattice — organs already placed at the fine arrangement, and the rule asked only to continue it — is asking whether the arrangement is stable rather than whether it is reachable, which is a different question with a possibly different answer.

A stem unrolled: 180 nodes at 136.78° with a rise of 0.013 circumferences. The counter is shown these coordinates and the circumference, and finds 5 parastichies one way and 8 the other. The faint strips left and right are the same stem: a family leaving one edge re-enters at the other.
Fig. 22 An arrangement built rather than grown, which is what such a test would start from.

That second experiment is the one this collection should want most. Reachability and stability are different properties, plants grow rather than being assembled, and a fine lattice that is stable but unreachable would be a genuinely interesting object.

The claim stated so it can fail

A wall is a universal negative and those are worth stating carefully, because a universal negative is refuted by one counterexample and this one has a small number of cases behind it.

What is claimed: under this placement rule, at this exponent and reach, grown from a seed of eight organs at a stated angle, a run that has not settled within 1,200 organs does not settle within 3,200. That is checked on forty-one runs across eight rises and nine starting angles.

What is not claimed: that no run anywhere ever settles late. Ten thousand organs have not been tried, and one run settling at organ five thousand would move this from a wall to a very expensive budget. The reason for not trying ten thousand is that the shape of the evidence already argues against it — settling times cluster under fifty, with one outlier at 290, so a settling at five thousand would be an outlier of a completely different kind rather than a further point on a tail.

How many organs a stem needs before it is on a lattice. One row per rise, one mark per starting angle, placed at the organ from which every later divergence stays within a degree and a half of the run's own final value. Where a stem settles at all it does so between 0 and 290 organs in, against the 400 every ablation run here grows before it cuts anything. Not one row needs the length it is given. What changes down the table is the count on the right: how many of the nine starting angles reach a lattice at all, which falls from 7 at the coarse rises to 1 at the finest.
Fig. 23 The distribution the argument rests on, whose longest arrival is 290 organs against a run of 3,200.

And what a reader can check cheaply: the whole table is nine starting angles at eight rises, and any one row is one run. A single run at 0.003 from any starting angle, grown as long as anybody likes, is the experiment — and it is the kind of check this collection prefers to leave stated rather than to pre-empt.

Two runs of the same rule from unrelated starting angles. Both settle at 137.0°, within 0.5° of the golden angle, from seeds 166° apart.
Fig. 24 The quantity such a check would watch, which is the same one every essay here has been reading.

What is left

The two experiments above, and one measurement that costs nothing. The failures have divergence sequences, and nobody has looked at them. Whether a failed run wanders across the whole range, or cycles, or sticks near one value while exceeding the tolerance, is readable from data already computed.

The block a wrecked stem settles into is the count it was cut from. A stem is cut in the middle of its front and followed for 300 organs. It does not come back to its lattice; what it does instead is repeat a fixed sequence of divergences exactly, to the resolution of the azimuth grid. Each row shows that sequence twice over, one bar per organ, drawn to the same scale. At the 5/8 rung the sequence is five angles long and advances -36.1° per block; At the 8/13 rung the sequence is eight angles long and advances 22.5° per block. Every block is the smaller number of the pair that was cut, so the second attractor carries the first one's count — and every precession is one part in twice the block, which makes each of these a two-jugate arrangement with 10 and 16 rows.
Fig. 25 The kind of reading that would answer it, applied elsewhere to sequences that repeat rather than settle.

And the question of what a plant would do, which this collection keeps arriving at and keeps declining to answer. Real stems at very fine rises exist and their arrangements are countable, so either plants are not running this rule, or they are running it from a starting condition that is already in a basin, or the wall is an artefact of growing from a seed of eight organs at an arbitrary angle. Nothing here distinguishes those, and the third is testable with the second experiment above.

Every open question here needs under 28 specimens. The sample size at which each comparison reaches 80 per cent power at a 5 per cent false-positive rate, from the exact binomial rather than a normal approximation. The census question — do plants show consecutive Fibonacci pairs far more often than the geometry does — needs 4: 14.7% is the share of divergence angles giving a consecutive Fibonacci pair at a fine rise; 90% is what a grown history gives.
Fig. 26 The survey that would settle the first of the three, whose size this collection has priced and cannot run.

What links here

Computed from the collection, not written here: the essays that point at this one.

Shares its objects with

Essays that name at least two of the same things, and that neither author linked.

Named objects

A flat tag is an object no other essay names yet.

AttractorBasinCounting blindControlHonest limitsInitial conditionLadderLatticeMeasurementModel scopeNegative resultRiseSettling timeTransitions