What a plant might be doing

A disturbance with a memory

The previous phase's control assumed that a plant's errors are independent from organ to organ, and nobody had tested it. Give the errors a memory — each one a fraction of the last, up to a coefficient of 0.97 — and the comb does not appear. The obvious threat to the result turns out to be empty, and the algebra says why before the measurement does.

Worth reading first: What a mechanism would have to show · The sequence has a memory · Where the noise gets in.

The previous phase ended with the strongest claim this site has made about mechanism, and it was a claim built on a control. Take a stem the placement rule grew, read the correlation between one divergence angle and the one eight organs later, and there is a comb in it — a run of lags at multiples of eight standing well above what a sample of that length wanders by on its own. Then build the same lattice kinematically: put node i at exactly i times the divergence, at the same rise, displace every azimuth by an independent draw, and read it the same way. Nothing. Largest comb mean 0.02 against a sampling band of 0.07, refused on every seed.

A lattice with independent errorsThe autocorrelation of 759 divergence angles from a kinematic lattice at a divergence of 137.8261° and a rise of 0.005, with 0.5° of scatter on each azimuth. There is no placement rule anywhere in it: node i is put at exactly i times the divergence and then displaced. The only thing that differs between this figure and the control is the structure of the displacement — here, independent errors — the previous phase's control at 0.5° of independent scatter. The largest comb mean is 0.029 against a sampling band of 0.073, and the readout refuses.-0.50000.500125810131621242629lag, in internodescorrelation between a divergence and the one that many internodes laterrefusedmain 0.029 · band 0.073sampling bandkinematic lattice · 759 anglesgenerated from a stated rule, not drawn to look right
Fig. 1 The control as the previous phase left it. A cylindrical lattice at a divergence of 137.8261° and a rise of 0.005, with half a degree of independent scatter on each azimuth and no placement rule anywhere in it. Its photograph is a real stem’s photograph and its parastichy pair is a real stem’s pair. Nothing in the thirty lags clears the band.

From that the phase concluded that the comb is not a property of the arrangement but of the rule that made it — the first observable on this site that separates a plant computing a pattern from a plant that merely has one.

Two combs, at a rise of 0.005The autocorrelation of 760 divergence angles from one stem held at a rise of 0.005. The filled teeth are the lags at multiples of 8; the open teeth are the second comb, at the same spacing offset by 5. Reading the spacing off the first and the offset off the second gives the pair 8 and 13, which is what the position counter reports for the same stem — from angles alone, with no coordinate anywhere in the calculation.-0.50000.500125810131621242629lag, in internodescorrelation between a divergence and the one that many internodes later816245132129spacing 8 · offset 5pair 8/13 — counter says 8/13sampling bandone stem · 760 divergences · disturbance 0.25generated from a stated rule, not drawn to look right
Fig. 2 The stem the rule grew, on the same axes. The filled teeth are the main comb and the open teeth the second, and reading the spacing off one and the offset off the other gives the pair the position counter finds in the same stem. Nought point six four against nought point nought two: the difference the previous phase’s headline rests on.

The phase plan then wrote down the assumption that conclusion depends on, and said it was the first thing the next phase should do. Every error in the control is drawn independently of every other one, and no plant’s errors are. An organ that comes out a little late affects the one after it; a shoot that grows through a cold night makes a run of organs that are all a little wrong together. If a disturbance with a structure of its own could put correlation into the angle sequence, the comb would be a fact about the weather rather than about the meristem, and the conclusion would be worthless.

This essay is the first half of that test, and the news is good. The obvious form of the worry — a disturbance that remembers — manufactures nothing at all.

What “correlated” has to mean

The phrase covers two different things and the difference is the whole essay.

A disturbance has a memory if today’s error resembles yesterday’s: the error at organ i is some fraction ρ of the error at organ i − 1 plus a fresh draw. That is the standard model of a quantity that drifts, and its correlation falls smoothly with separation — strong between neighbours, weaker two apart, gone by twenty. It has a length.

A disturbance is periodic if the error returns to the same value at a fixed separation: every eighth organ gets the same displacement, whatever happens in between. Its correlation does not fall with separation at all; it comes back. It has a period.

Everyday usage calls both of them correlated noise, and the readout this site built is built to find one of them and is blind to the other. A comb is a set of teeth at multiples of a spacing. A memory has no teeth.

A lattice with an error that remembers the last oneThe autocorrelation of 759 divergence angles from a kinematic lattice at a divergence of 137.8261° and a rise of 0.005, with 0.5° of scatter on each azimuth. There is no placement rule anywhere in it: node i is put at exactly i times the divergence and then displaced. The only thing that differs between this figure and the control is the structure of the displacement — here, an error that remembers the last one at ρ = 0.9. The largest comb mean is 0.013 against a sampling band of 0.073, and the readout refuses.00.2500.5000.75025810131621242629lag, in internodescorrelation between a divergence and the one that many internodes laterrefusedmain 0.013 · band 0.073sampling bandkinematic lattice · 759 anglesgenerated from a stated rule, not drawn to look right
Fig. 3 The same kinematic lattice, with the independent draws replaced by an AR(1) process at ρ = 0.9 — an error that keeps nine tenths of the last one. The scatter is identical, the divergence is identical, the arrangement is identical to any counter shown its coordinates. The largest comb mean is 0.014 against a band of 0.073, and the readout refuses.

The algebra, which is one line

The reason a memory cannot make a comb is available before any stem is grown, and writing it down first is what makes the measurement a test rather than an exploration.

What a botanist writes down is not the error at each organ. It is the divergence, the angle from one organ to the next, and that is the difference of consecutive azimuth errors. If the errors have covariance γ(k) at separation k, then the differences have 2γ(k) − γ(k−1) − γ(k+1) at the same separation — a second difference, with a minus sign. For an AR(1) error, γ(k) = ρ^k, and that expression collapses to −ρ^(k−1)(1 − ρ)². Divide by the variance of the differences, which is 2(1 − ρ), and the correlation at lag k is −ρ^(k−1)(1 − ρ)/2.

Negative, monotone, decaying. At ρ = 0.9 it is −0.05 at lag one and −0.02 at lag four and −0.005 at lag ten, and at every lag in between it is on the same smooth curve. There is no lag at which it stands above its neighbours, which is the only thing a comb search can see. The spacing search looks for a residue class whose members average higher than the classes around it, and a curve that is the same shape everywhere gives every class the same average.

Notice also which way the coefficient pushes. As ρ rises the factor (1 − ρ) falls, so a longer memory produces a weaker signature in the differences. In the limit of a perfect memory the error is a constant offset, every divergence is the same, and the disturbance has vanished from the measurement entirely. The threat gets smaller as the thing feared gets bigger.

A memory manufactures nothingThe largest comb mean found in a kinematic lattice whose azimuth errors are an AR(1) process, against the coefficient of that process, over eight seeds at each point. The dashed line is where the rule's own stems sit, at 0.64; the shaded strip is three sampling bands. Every point is inside the strip — 0.028, 0.026, 0.022, 0.014, 0.015 at ρ = 0.3, 0.5, 0.7, 0.9, 0.97 — and the readout returns nothing on 40 runs out of 40. A correlated error is not a periodic one.00.2000.4000.6000.3000.5000.7000.9000.970how strongly each error remembers the last, ρthe largest comb mean anywhere in the thirty lagsthe rule's own stems: 0.64three sampling bands0.0280.0260.0220.0140.015kinematic lattice · AR(1) errorgenerated from a stated rule, not drawn to look right
Fig. 4 The largest comb mean anywhere in the thirty lags, against how strongly each error remembers the last, on eight seeded lattices per point. Every value is inside three sampling bands, the readout returns nothing on all forty runs, and the curve falls as the memory lengthens — which is the sign the algebra predicts and not one that had to come out that way.

What the measurement adds

If the algebra is right, why measure at all? Because the algebra is about a model of the disturbance and the figure is about a stem. Three things could have gone wrong between them, and each is worth naming.

The readout is not the correlation. It is a search over spacings, over residue classes, over thresholds that themselves depend on how many members a comb has. A search with several free choices in it can find structure in a smooth curve, and a search that finds a spacing in an AR(1) sequence would be a defect in the instrument rather than a fact about plants. It does not: the spacing it returns wanders from seed to seed and never clears its own band.

The scatter is not held fixed by the algebra. Every shape here is normalised to unit variance before the amplitude is applied, so a lattice with a memory has the same recorded scatter as the control. Without that the comparison would be between disturbances of different sizes and any difference in the readout would follow the size.

And the arrangement could have stopped being a lattice. A correlated error accumulates differently from an independent one, and an arrangement whose points have wandered off the lattice would refuse for the wrong reason. It has not: at ρ = 0.97 the recorded scatter is the half degree it was asked for, and the position counter reads the same parastichy pair it reads from the control.

A lattice with an error that remembers the last oneThe autocorrelation of 759 divergence angles from a kinematic lattice at a divergence of 137.8261° and a rise of 0.005, with 0.5° of scatter on each azimuth. There is no placement rule anywhere in it: node i is put at exactly i times the divergence and then displaced. The only thing that differs between this figure and the control is the structure of the displacement — here, an error that remembers the last one at ρ = 0.5. The largest comb mean is 0.024 against a sampling band of 0.073, and the readout refuses.00.50025810131621242629lag, in internodescorrelation between a divergence and the one that many internodes laterrefusedmain 0.024 · band 0.073sampling bandkinematic lattice · 759 anglesgenerated from a stated rule, not drawn to look right
Fig. 5 A shorter memory, ρ = 0.5, for comparison with the long one above. The two are on the same axes and there is no visible difference: nothing at any lag, at either coefficient. What the algebra says is that the coefficient controls only how fast an already-featureless curve decays.

The memory this essay did not put anywhere

There is a third place a memory could live and it is not the place tested above, which is worth saying plainly rather than leaving for a reader to notice.

The disturbance here is in the arrangement. Node i goes where the divergence says and is then displaced, and the displacements are correlated with one another. That is the right experiment for the question asked, because the previous phase’s control was an arrangement and a control is contradicted on its own ground or not at all.

A real plant’s disturbance is more likely to be in the rule: the meristem’s next organ is placed against a field that is a little wrong, or against neighbours that have moved since they were put there, and the error at one organ therefore feeds into where the rule puts the next. This site has three names for those — field, placement and jostle — and each of them was given an amplitude two phases ago and none has ever been given a correlation length. A jostle whose displacements were correlated from organ to organ is a different object from the lattice measured here, because the rule responds to it: the placement rule is self-correcting, so a run of errors pushing the same way meets a restoring push that an independent run does not.

Whether that changes the comb is open. The algebra above does not settle it, because the algebra assumes the errors go into the azimuths and come out in the differences with nothing in between, and a rule is exactly a something in between. The prediction worth writing down before anyone measures it is that a self-correcting rule shortens whatever correlation length it is given — the correction acts on the accumulated error, so a memory in the input becomes a shorter memory in the output — and therefore that this essay’s negative result holds a fortiori. A prediction that a later phase can refute is worth more than a hedge, and this is one.

What it would take is one option on grow: a stream of disturbances with a stated structure rather than a stream of independent draws. It is half an hour of work and it is not done here, because the phase’s budget went to the shape that turned out to forge everything, and doing it badly at the end of a phase is how a number nobody checks gets into a plan file.

Where this leaves the previous phase’s claim

Exactly where it was, and no further. The control has survived the first correlated disturbance put to it, which means the comb is not an artefact of assuming independence in the way that was worried about. It does not mean the comb is evidence of a placement rule, because a memory is only one of the shapes a disturbance can have.

It is worth being precise about what has and has not been shown, because this site has a standing habit of stating what a result does not cover and this is a case where the uncovered part is larger than the covered one.

Shown: a disturbance whose correlation falls with separation cannot produce a comb in the differences, for any correlation length, and the reason is arithmetic rather than empirical.

Not shown: that no disturbance can. The class of disturbances is much larger than the class of AR(1) processes, and the next essay puts a periodic one into the same lattice and gets a comb out of it. The one after that puts in the disturbance a plant would actually have — errors passed between the organs that touch each other — and gets the comb and the pair.

Which arrangements carry a comb, and what each one reportsThe largest comb mean in five arrangements at a rise of 0.005, all read by the same instrument at the same length, with the sampling band of 0.073 marked. Only the first is a placement rule; the other four are kinematic lattices with no rule in them, differing from one another only in how their azimuth errors are structured. Independent errors and errors with a memory leave nothing to read. A repeating error puts up a comb and names a partner that is not the lattice's. Errors inherited from the contact neighbours reproduce both the comb and the pair.three sampling bandsthe placement rule0.6428/13independent errors0.031refusedan error with a memory0.014refusedan error that repeats0.4338/10, 8/12errors passed between neighbours0.5538/13one rule, four kinematic latticesgenerated from a stated rule, not drawn to look right
Fig. 6 The five arrangements this thread ends up comparing, and where this essay’s result sits among them. The second and third bars are the two that leave nothing to read. The fourth and fifth are the subject of the two essays that follow, and neither of them has a placement rule in it either.

Two things this thread has been careful about since it began

The distinction between a length and a period is not new here. It is the same distinction the noise thread had to make when it asked whether noise is a slow rate, and the answer had the same shape: two quantities that are described with one word in the literature and behave differently when each is given a knob of its own.

Three disturbances, three places to get inThe rule reads its neighbours, builds a profile of the energy at every azimuth, takes the least of it, and records a position. field noise enters at the profile; jostle noise enters at the neighbours; placement noise enters at the record. Two of the three are upstream of the choice and can change which minimum is taken; the third is downstream and never can.upstream of the choicethe neighboursalready placedthe profileenergy by azimuththe choicethe least of itthe recordwhat a ruler readsfield noisejostle noiseplacement noiseone rule, three entry pointsthe order is the argument
Fig. 7 The three places a disturbance can enter the placement rule, which is the distinction this site drew two phases ago and which is orthogonal to the one drawn here. That one is about where the error arrives; this one is about how errors at different organs are related to each other. A disturbance has both properties and the readout responds to only one of them.

The other half of the care is about what the sequence statistic already knew. The lag-one statistic reads the correlation between one divergence and the next — lag one, deliberately excluded from the comb search because a single misplaced organ enters two consecutive divergences with opposite signs and puts a large negative value there whatever else is true.

That statistic is not blind to a memory. It is the one place where the AR(1) signature shows up, and it shows up exactly where the algebra puts it: the lag-one correlation of a lattice with a memory runs from −0.55 at ρ = 0.3 to −0.10 at ρ = 0.97, climbing towards zero as the memory lengthens, while the rule’s own stems sit near −0.6 regardless.

The memory of a divergence sequence, at 0.75° of scatterWith no noise at all the lag-one correlation is 0.54: the rule corrects itself, so a lattice arrives with a memory in it. Matched at the same recorded scatter, placement noise leaves -0.09, jostle noise leaves 0.67, field noise leaves 0.51. The band is ±0.13, which is what an uncorrelated sequence of this length gives.-0.25000.2500.500123456lag, in nodescorrelation between a divergence and the one that many nodes laterno noiseplacement noisejostle noisefield noisesampling band5 runs each · 243 divergences per runmatched at 0.75° of scatter
Fig. 8 The lag-one statistic on the rule’s own stems, which is the measurement this site made two phases ago and the one a memory does interfere with. The value is a property of the placement rule’s self-correction; a kinematic lattice with a memory would sit at a different value with no rule anywhere, which is why the lag-one number was never the evidence and the comb was.

So a botanist who could measure the correlation length of a plant’s disturbances would learn something — but not from the comb, which does not respond to it.

What the sequence sees that the scatter cannotEach point is an ensemble at one amplitude, placed at the scatter it produces. A stem at three quarters of a degree of scatter has a lag-one correlation near zero if its noise arrived after the primordium was placed, and near 0.7 if it arrived before — and no measurement of the scatter can tell those apart. The separation closes above about a degree, because what the other two kinds preserve is the correlation of a lattice.00.2000.4000.6000.5000.75011.251.50divergence scatter, in degrees — the one quantity a plant offerscorrelation between one divergence and the nextplacement noisejostle noisefield noise5 runs per point · band ±0.13every point is a lattice
Fig. 9 And the reason lag one cannot carry the argument on its own: it moves with the scatter, which is a quantity a plant has for a dozen reasons. The comb’s virtue was supposed to be that it does not.

The test as it will be handed to a plant

The specification this thread has been assembling for four phases gains nothing from this essay, which is the honest way to report a negative result: it removes a term rather than adding one.

Before this measurement, a survey that found a comb in a real stem’s angles would have had to argue that the plant’s disturbances were not correlated — an argument nobody could make, because nobody has measured a plant’s disturbance autocorrelation and the measurement is harder than the one the comb was supposed to support. After it, that argument is not needed. A memory of any length is consistent with a clean comb and with no comb at all, so finding one says nothing either way about correlation length, and the survey does not have to control for it.

What the experiment costs, in internodesThe combined sampling band of two autocorrelations falls as one over the root of the sequence length. The difference to be resolved is 0.76 — between noise that arrives before the primordium is placed and noise that arrives after — so the count needed is 56 internodes on a single stem. Every other open question in this collection is priced in tens of specimens.00.2500.5000.750100200300internodes counted on one stemsmallest difference in correlation the count can resolvethe difference to resolve — 0.7656 internodesmatched at 0.75° of scatterone stem, counted once
Fig. 10 What the readout costs in stem length, which is the quantity the specification is actually made of and which this essay leaves untouched. A negative result that removes a control from a specification is worth as much as a positive one that adds a number to it, and it is worth less than it looks: the control it removes was never the binding one.

What the survey does have to control for is the other shape, and the next two essays are about how expensive that turns out to be.

It is worth putting the two results side by side in the form a specification uses, because they pull in opposite directions and the pair of them is the honest summary of this thread’s standing.

A correlation length costs nothing. No length, from a tenth of an organ to thirty of them, produces a comb, and none destroys one either — the rule’s own stems keep their comb whatever the disturbance’s autocorrelation, because the comb comes from the neighbour structure and not from the disturbance’s shape. So a survey need not measure it, need not report it, and need not exclude plants that have it.

A periodicity costs everything. A disturbance that returns to the same value every m organs puts a comb at m on an arrangement with no rule in it, and a survey that found a comb without excluding that possibility would have found nothing at all. Excluding it is the subject of the two essays after this one, and the short version is that it cannot be excluded from a single stem.

Three kinds of noise, matched at 0.75° of divergence scatterThe amplitudes differ — field 0.0056 (fraction of the barrier), jostle 0.15 (degrees of azimuth), placement 0.18 (degrees of azimuth) — and are in different units, so they cannot be compared directly. What can be compared is what they produce, and matched here they are within 27% of one another. Everything a finished pattern records about its noise is shared between the three.field — before the choice0.92°amplitude 0.0056jostle — before the choice0.70°amplitude 0.15placement — after it0.79°amplitude 0.183 runs each, at the amplitude that reaches 0.75°27% apart on the ruler
Fig. 11 The standing warning this thread carries into every result: two disturbances that a ruler cannot tell apart can differ in everything about which minimum the rule chose. A memory and a periodicity have the same recorded scatter, the same distribution of divergences, and the same photograph — and one of them forges the phase’s headline observable and the other does not.
Transported errors report the same pair every timeeight kinematic lattices, differing only in the seed of their disturbance, each read by the same instrument. The disturbance at each node is inherited from the nodes 8 and 13 places back, at a coupling of 0.5. Every stem returns 8/13, which is the pair the positions give and the pair the placement rule's own stems give. There is no placement rule in any of these arrangements.stemwhat the angles say18/13the lattice's own pair28/13the lattice's own pair38/13the lattice's own pair48/13the lattice's own pair58/13the lattice's own pair68/13the lattice's own pair78/13the lattice's own pair88/13the lattice's own pairthe positions say 8/13kinematic lattice · inherited errorgenerated from a stated rule, not drawn to look right
Fig. 12 And what the next two essays find, put here so this one’s negative result is not read as the end of the matter. Eight kinematic lattices whose errors are passed between contact neighbours, every one returning the pair — a disturbance that comes back rather than one that fades.

Reads more easily once this is understood

Essays that name this one as worth reading first.

Shares its objects with

Essays that name at least two of the same things, and that neither author linked.

  • What a forgery has to know — both name autocorrelation, discrimination, evidence, honest limits, measurement, noise, null model, parastichy pair, the placement rule
  • What one angle says about the next — both name autocorrelation, discrimination, divergence angle, ensemble, measurement, measurement error, noise, the placement rule, self correction
  • A harmonic is a step taken twice — both name artefact, autocorrelation, divergence angle, lattice, measurement, parastichy pair, the placement rule, self correction
  • A refusal with a reason — both name autocorrelation, discrimination, divergence angle, ensemble, honest limits, measurement, measurement error, parastichy pair
  • The comb was never the rule — both name autocorrelation, discrimination, evidence, honest limits, measurement, null model, the placement rule, self correction
  • The control a survey would need — both name autocorrelation, discrimination, evidence, honest limits, measurement, measurement error, null model, parastichy pair

Named objects

A flat tag is an object no other essay names yet.

ArtefactAutocorrelationDiscriminationDivergence angleEnsembleEvidenceHonest limitsLatticeMeasurementMeasurement errorNoiseNull modelParastichy pairThe placement ruleSelf correction