A periodicity is not a lattice

A memory in a plant’s disturbances manufactures nothing, and the reason is that a memory decays. The thing that would manufacture a comb is a disturbance that returns — one that comes back to the same value at a fixed separation instead of fading away from it. This essay builds that disturbance deliberately, drives it into a lattice with no rule anywhere in it, and reads the result with the same instrument.

It works. A comb appears, at the spacing it was given, well clear of the sampling band.

So the previous phase’s control is not sufficient on its own. Independence was doing work in it, and a disturbance that is not independent in the right way puts up the phase’s headline observable for free.

What saves the result — and it does survive, in a weakened form — is that the forgery is bad at the second number, and the site’s own habit of reading more than one stem is what exposes it.

What the forgery gets right, and what it invents #

The readout returns a pair. It finds a spacing by looking for the residue class whose members average highest, and it finds a partner by looking for a second class at the same spacing. On the forged stem the spacing is 8, which is right, because 8 is what the disturbance was built to repeat at.

The partner is where it comes apart.

The partner is not a measurement at all. Here is why, and the arithmetic is short enough to check by hand.

A disturbance that repeats with period 8 has a covariance that depends only on the separation modulo 8. Whatever the fixed pattern happens to look like — and it is drawn once per stem, so it looks different on every stem — its circular autocorrelation at offsets 1 through 7 is a set of seven numbers of order one over the square root of eight, with signs that are an accident of the draw. Those seven numbers reappear at every lag congruent to them: the value at lag 2 is the value at lag 10 is the value at lag 18.

So a periodic disturbance does not put up one comb. It puts up eight of them, one per residue class, and seven are junk. The readout picks the tallest of the seven, and which one is tallest is a property of the pattern that was drawn for this stem. Change the seed and a different class wins.

That is why the answers run 10 and 12 rather than clustering near 13. There is nothing about 13 in the disturbance at all. The forger knows one number, and the readout demands two.

The junk classes are not small, either, which is why they get through. A random pattern of length eight has circular correlations at offsets 1 to 7 that scatter around zero with a spread of roughly one over the square root of eight — about a third — and the periodic part of the disturbance carries seven tenths of the variance, so the tallest of the seven arrives at the readout at something like a quarter. The threshold a second comb has to clear is three sampling bands divided by the square root of its own length, which for a four-member comb is about a tenth. A quarter clears a tenth comfortably. The forgery’s partner is not squeaking past a test; it is passing it by a factor of two, on a quantity with no information in it.

That is worth stating as a general caution rather than as a fact about this forgery. A threshold set by sampling noise does not protect against structure that is not the structure being looked for. The band in every figure here is what a correlation wanders by when there is nothing there; it says nothing about what a correlation does when there is something there that is not the thing being measured.

The check that catches it is a second specimen #

Everything above is invisible from one stem. A botanist handed a single forged angle sequence would read a clean comb at spacing 8, a partner clearing the band, and would report a pair — with no way to know that a second plant of the same species, disturbed the same way, would report a different one.

So this essay changes the specification, and it changes it in the direction the survey thread has been pushed twice already. The pair must be read on several stems, and the readings must agree.

That is not a statistical nicety about averaging out noise. It is the only test that separates a lattice from a periodicity, because the lattice is a property the stems share and the periodicity is a property each stem draws for itself. The rule’s own stems agree with each other and with the position counter; the forgery agrees with nothing.

The site has had the habit for four phases and it was never justified this sharply. The reason to run five seeds was that any one of them might be unlucky. The reason now is that a single stem cannot distinguish a pattern from a disturbance that repeats.

Why the forger cannot simply be told the second number #

The obvious repair, from the forger’s side, is to use a disturbance that repeats at 13 as well as at 8. That is possible and it is the subject of the next essay, where it is built out of something a plant plausibly has rather than out of two periods chosen by hand. But it is worth noticing first what happens with a periodicity at 13 alone, because the answer is not what a reader would guess.

The reason is the readout’s own arithmetic, and it is the same constraint that turns up from the other direction in the essays about the fine end of the ladder. A comb has to have three teeth inside the lag window before it is called a comb — two lags at a common spacing is a coincidence available at every spacing — and the window is thirty lags. So the largest spacing the search can return is ten. A period of 13 has teeth at 13, 26 and 39, and the third is outside the window; the search never proposes 13 as a spacing, so it never finds the comb that is sitting there.

This cuts both ways and both are worth having.

For the forgery: a disturbance repeating at the larger parastichy number is invisible, so a forger has to know the smaller one specifically. Knowing “some number in this plant’s arrangement” is not enough.

For the instrument: there is a whole class of real periodicity the readout would miss, and the miss is silent. A stem whose disturbance repeats at 13 would be reported as having no comb, which under the previous phase’s reading would have been evidence that no rule made it.

Could a plant’s disturbance have a period? #

The forgery above was built by hand, and a forgery built by hand is only worth worrying about if something in the world could build it. Three candidates are worth naming, and the third is the one that matters.

A daily cycle beating against the plastochron. Organs are produced at roughly regular intervals, and the environment varies on a twenty-four-hour cycle, so a plant producing one organ every fraction of a day would receive a disturbance that repeats every few organs. This is real and it is not the threat: the period it produces is set by the ratio of two times, which has no reason to be a whole number and every reason to drift as the plant grows. A period that drifts is a memory with extra steps — the correlation smears across neighbouring lags and the comb loses its teeth.

An oscillation in the meristem itself. Some models of primordium initiation have a genuine clock in them, and a clock with a period of a few plastochrons would put structure at the lag of that period. Again the number is set by the clock rather than by the pattern, so it would have to coincide with the smaller parastichy number by accident — and it would go on repeating at the same lag while the pattern climbed the ladder and its parastichy numbers changed, which is a prediction a real stem could refute in one reading.

And the one that is not an accident: the neighbours. The organs that touch an organ are, by the definition of a parastichy pair, the ones m and n places back in the order of production. So any disturbance transmitted through contact — a physical push, a shared vascular connection, a local depletion of something — is correlated at exactly the lags the readout examines, and it is correlated at them because they are the lattice’s, not by coincidence.

That third candidate is the real threat and it is the subject of the next essay. It is worth seeing clearly what makes it different from the forgery here: this essay’s disturbance knows one number, chosen by whoever built it. A neighbour-transmitted disturbance knows both numbers, and does not have to be told them, because it lives on the arrangement whose numbers they are.

Which also disposes of the reassurance the previous section might otherwise offer. Reading several stems catches a forger who has to pick a period, because the period is a free parameter and the seven junk classes come out differently each time. It does not catch a disturbance whose period is a property of the lattice, because then every stem of the species has the same one.

A lattice is not a list of periods #

The title is the point and it is worth stating as a claim rather than as a summary.

A phyllotactic lattice is a set of points on a cylinder with a metric on it. Its parastichy numbers are the index offsets whose two organs come out closest together on the surface — which is a fact about the geometry, and the reason the numbers are Fibonacci is that a nearly-golden divergence makes those the short hops. The offsets are related to each other: 21 is 8 plus 13 because the vector to the 21-neighbour is the sum of the vectors to the other two, and this site measured two phases ago that every contact family but the two smallest is a sum of two others.

A periodic disturbance has none of that structure. It has one period and seven accidents. It reproduces the symptom the readout was built to detect and none of the arithmetic underneath it, and the arithmetic is what the second comb was found to be made of one phase ago: the second comb sits at the difference of the pair because correlation travels between neighbours and a one-step chain reaches offsets a·m + b·n with b = 0 or ±1.

So the forgery in this essay is a forgery of a statistic, not of a lattice. That is a real weakness of the statistic and it is why the previous phase’s control was too weak. It is also why the repair is available: demand the part of the statistic that reflects the arithmetic, on more than one plant.

What the specification now says #

Three requirements, each added by a measurement rather than by caution.

Several stems, and the readings must agree. From this essay. A single stem cannot separate a lattice from a period, and the disagreement between forged stems is visible with as few as three.

The angle reading must agree with a position count on the same stem. From the previous phase, and now doing much more work than it was asked to. The forged stems all have the same positions and therefore the same counted pair, so the counter contradicts four of the five that report.

And a refusal is not evidence of anything. From the figure at 13 above. The readout’s window means a periodicity at the larger parastichy number leaves no trace, so “no comb” cannot be read as “no periodicity”, and — under the previous phase’s interpretation — could not have been read as “no rule” either.