The claims, measured

What the pair costs

The single parastichy number cost sixty internodes. The pair costs two hundred and fifty, and a protractor error of three quarters of a degree takes it to eleven hundred. The arithmetic that predicts the second of those is right about the shape and wrong about the scale by a consistent factor, which is recorded rather than fitted away.

Worth reading first: The survey this site cannot do · The sequence has a memory · How many plants would it take.

An instrument is worth what it costs to use. This site has priced several — how many specimens a frequency claim needs, how many junctions distinguish two branching laws, how many internodes the single-number readout wants — and the prices have been more useful than most of the positive results, because a specification is something a person can act on.

So: what does the pair cost?

Internodes

Two hundred and fifty divergence angles from one stem, at the rise where the readout works best, with no reading error at all. Five stems out of five return the pair the position counter finds at 250 and above; four out of five at 150 and at 200.

The single number cost sixty. The pair costs about four times that, and the reason is visible in the two scores rather than being a matter of statistical taste: at this rise the main comb averages 0.64 and the second averages 0.50, and both have to clear a threshold that falls only as one over the square root of the length. The weaker comb sets the price.

What the pair costs, at a rise of 0.005Five seeded stems at each length, read at four protractor errors. With no reading error the pair needs 250 internodes — against the sixty the single parastichy number costs. At 0.25° per organ it needs 250; At 0.5° per organ it needs 400; At 0.75° per organ it needs 1100. The pattern's own scatter here is 0.70°, so the last of those is a reading error larger than the signal being read.0123451502504007601.1e+3internodes measured on one stemstems out of five returning the counted pairno reading error0.25° per organ0.5° per organ0.75° per organrise 0.005 · disturbance 0.25 · pattern scatter 0.70°generated from a stated rule, not drawn to look right
Fig. 1 Five seeded stems at each length, at four protractor errors. The topmost curve is the readout with no reading error: it reaches five out of five at two hundred and fifty internodes and stays there. The lower curves are the same experiment with an error added to each recorded position, and they are the subject of the rest of this essay.

Two hundred and fifty internodes is a real requirement and it is worth saying what kind of plant supplies it. Not a rosette, which has no internodes to speak of. Not a cone or a capitulum, where the organs are on a disc and there is no sequence to walk up. A long unbranched shoot with visible leaf scars, and enough of it that the parastichy pair does not change over the stretch measured — which is the rate condition, and it has its own essay.

What the experiment costs, in internodesThe combined sampling band of two autocorrelations falls as one over the root of the sequence length. The difference to be resolved is 0.76 — between noise that arrives before the primordium is placed and noise that arrives after — so the count needed is 56 internodes on a single stem. Every other open question in this collection is priced in tens of specimens.00.2500.5000.750100200300internodes counted on one stemsmallest difference in correlation the count can resolvethe difference to resolve — 0.7656 internodesmatched at 0.75° of scatterone stem, counted once
Fig. 2 The earlier statistic’s price, for comparison. The lag-one correlation separates noise arriving before the rule’s choice from noise arriving after it, and it does so on about sixty internodes. Everything the pair adds is paid for in the difference between that number and two hundred and fifty.

The protractor

The binding constraint on the single-number readout turned out to be precision rather than length, and it is worse here.

A reading error enters the recorded divergences in a particular way, and the way matters. An observer marks where each organ is and subtracts to get the gaps, so an error of ε on one organ’s azimuth enters two consecutive divergences with opposite signs. That makes the error a moving average of variance 2ε², which puts a large negative correlation at lag one — where nothing is being read — and adds variance at every lag.

The pattern’s own contribution to the correlation at a comb’s lags is untouched by the error. What changes is what it is divided by. So every correlation dilutes by the ratio σ² / (σ² + 2ε²) for a pattern scatter σ, which is the law the previous phase measured to within three per cent while there was signal.

Now set that against the threshold. The threshold a comb has to clear falls as one over the square root of the number of divergences. So recovering a diluted comb needs the threshold to fall by the dilution factor, which needs the length to grow by the square of it: N(ε) = N(0) · (1 + 2ε²/σ²)².

There is nothing free in that. The dilution law came from the previous phase, the threshold’s dependence on length is the sampling band’s, and neither was fitted to anything measured here.

The prediction against the measurement

The pattern scatter on these stems is 0.70°. Feeding that in, the law says the pair should need 250 internodes at no reading error, 395 at a quarter of a degree, 1,027 at half a degree and 2,741 at three quarters.

Measured, it needs 250, 250, 400 and 1,100.

The shape is right and the scale is not. The measured curve rises steeply, monotonically, and by roughly the amount predicted between the last two points — a factor of 2.75 measured against 2.67 predicted. What is wrong is that every prediction is too large, by 1.6, 2.6 and 2.5, in the same direction at every point.

A consistent over-prediction is a different kind of error from a scattered one. It is the signature of one input being systematically mis-measured rather than of the law being wrong, and the input in question is not hard to identify: σ is taken as the root mean square of the whole divergence series, and only the part of that variance which is correlated carries the comb. A larger effective σ moves every prediction down by the same factor. Solving for the σ that would fit gives about 1.4°, or twice the measured RMS, which would mean roughly a quarter of the variance is incoherent — plausible and unverified.

It is recorded that way rather than repaired by fitting σ. A fitted σ turns a prediction with nothing free in it into a curve with one parameter, and a curve with one parameter that passes through four points is not evidence of anything. The useful content survives either way: a coarser protractor is paid for at something like the fourth power of the error, so doubling the reading error costs about sixteen times the stem.

The measurement is limited by the protractor, not by the plantThe peak falls as the reading error grows, and it falls by an arithmetic factor with nothing fitted: a position error enters two consecutive divergences with opposite signs, adding variance at every lag while the pattern's signal sits at one. At a quarter of a degree the readout is right on all 3 runs; at half a degree on 2; at a degree on 0. Below the dashed floor the peak is the largest of thirty noisy numbers rather than a measurement.00.2000.4000.6000.80000.50011.502reading error on each organ's position, in degreesheight of the peak at the parastichy numberwhat noise alone givesthe threshold a reading must clear3/3 right3/3 right2/3 right0/3 right0/3 rightpredictedrise 0.005 · 3 runs · pattern scatter 0.68°peak × σ²/(σ² + 2ε²), nothing fitted
Fig. 3 The same dilution law tested on the single-number readout, where it was measured to within three per cent. The prediction is the same arithmetic; what differs here is that the pair’s threshold has a comb length in it as well, so the length required goes as the square of what the peak height does.

Why a quarter of a degree is the number to quote

At a quarter of a degree per organ the pair costs nothing extra: 250 internodes, the same as with no error at all. At half a degree it costs 400. At three quarters it costs 1,100 — and at one degree the readout does not clear at any length tried.

So the specification has a cliff in it rather than a slope, and the cliff sits just past half a degree, which is around the pattern’s own scatter. That is not a coincidence: the dilution is a ratio of the reading error to the pattern’s scatter, so an instrument that reads a pattern to worse than the pattern’s own departures is measuring its own noise.

A field protractor against a stem will not do a quarter of a degree. The previous phase said so about the single number and the sentence stands unchanged: this is photogrammetry, or a stem cleared and imaged, and it is the line in the specification that has changed what a survey would cost more than any other.

Both vary; only one of them varies enough to findEach organ's step exponents, divided by its own mean so the two are comparable. The ogive's run over 15 per cent of their mean across 5 rings. The convex head's run over 1.15 per cent across 5 — inside the band a 2 per cent error on each ring position leaves, so no ruler separates it from a flat disc.0.9000.95011.0501234which step of the ladderexponent ÷ its meanan ogive — 15%a convex head — 1.15%what 2% per ring allows5 rings on the ogive · 5 on the head15% against 1.15%
Fig. 4 The general shape of the problem, from the phase that met it on cones: a quantity is measurable when the difference it makes exceeds what the measurement error allows, and the boundary moves with the error rather than with the care taken. The pair’s boundary sits at about half a degree per organ.

What is bought for the price

It is worth setting the cost against what the cheaper instruments give, because the pair is not the only thing a sequence carries.

  • Sixty internodes and a rough protractor give the lag-one correlation, which separates noise arriving before the placement from noise arriving after it.
  • Sixty internodes and a quarter of a degree give the smaller parastichy number, from the main comb alone.
  • Two hundred and fifty and a quarter of a degree give the pair, and therefore the branch.
  • A photograph gives the pair too, when the spirals are traceable, and gives it in an afternoon.

The last of those is the comparison that keeps the result honest. Where the spirals can be counted, counting them is enormously cheaper and this instrument is a curiosity. Its value is where they cannot: material where the organs are gone and only the scars remain, a stem too long or too irregular to photograph as a whole, or a specimen where the question is not the count but whether the sequence has a memory in it — which no photograph can answer, and which is what the mechanism essay is about.

What each report rules outThe divergence axis from 20° to 180°, with the angles consistent with each reported pair marked on it. 3/5 allows 14.4° of it; 34/55 allows 0.118°, which at this scale is thinner than the line drawn for it. The golden angle is marked because every one of these bands contains it.20°60°100°137.5°180°137.51°3/514.4°5/85.5°13/210.811°34/550.118°every band contains the golden angle — what changes is how much else it containsdivergence swept 20°–180° · edges bisected14.4° down to 0.118°
Fig. 5 What a photograph’s count is worth on the same scale: the band a reported pair leaves in the divergence angle narrows as the product of the two numbers. A pair counted high on the ladder is a far better measurement of the angle than a pair counted low, which is the fact that decides which specimens are worth photographing.

The specification, in one paragraph

For the record, and in the form the survey file keeps them:

To read a parastichy pair from angles alone. One shoot, unbranched, with at least 250 consecutive internodes over which the pair does not change — which requires a rate slower than about 250 nodes per rung, measured in its own essay. Azimuths to a quarter of a degree per organ; half a degree costs sixty per cent more stem, and one degree does not work. The plant must be disturbed enough for its divergences to vary — a scatter of half a degree to one degree in the model — and not so disturbed that the lattice is gone. Report the spacing of the main comb, the residue of the second, the pair that follows, and the three clearance tests, so that a refusal is distinguishable from an absence of data.

Every open question here needs under 28 specimensThe sample size at which each comparison reaches 80 per cent power at a 5 per cent false-positive rate, from the exact binomial rather than a normal approximation. The census question — do plants show consecutive Fibonacci pairs far more often than the geometry does — needs 4: 14.7% is the share of divergence angles giving a consecutive Fibonacci pair at a fine rise; 90% is what a grown history gives.plants show consecutive Fibonacci pairs far more…4and more often even than a coin weighted to a half10a conifer cone's rings are spaced as a cone rather…1multijugate patterns are a real minority rather than…28against 14.7%, if the truth is 90%needs: the pair, at a stated rungagainst 14.7%, if the truth is 50%needs: the pair, at a stated rungagainst φ² = 2.62, if the truth is φ^(2/1.88) = 1.67needs: three ring positions, to ±3%against 2%, if the truth is 15%needs: the pair; the whorl's symmetryspecimens neededexact binomial · α = 0.05 · power 0.81 to 28 specimens
Fig. 6 The other half of any survey this site specifies: how many specimens a claim about a population needs, which is a separate cost from how much stem a claim about one plant needs. The two multiply, and it is the product that has kept the survey unpaid for six phases.

Why the threshold is sharp rather than gradual

The length curves have an odd shape and it is worth explaining, because a reader who expects a gentle rise in reliability will read the figure wrongly.

At no reading error the readout is right on four stems of five at a hundred and fifty internodes, five of five at two hundred and fifty, and five of five at every longer length tried. It does not creep up; it steps.

That is what a threshold on a mean does. The comb score is roughly independent of length — a longer sequence estimates the same correlation more precisely rather than a larger one — while the threshold it has to clear falls as one over the square root of the length. So the question at each length is whether a fixed number has crossed a falling line, and the answer flips over a narrow range of lengths rather than improving steadily.

Which means the number to quote is a threshold rather than a rate, and the honest form of the specification is “two hundred and fifty internodes” rather than “more is better”. Past the threshold, extra stem buys nothing at all: the pair at eleven hundred internodes is the same pair as at two hundred and fifty, with a slightly larger margin.

What extra stem does buy is tolerance of a worse protractor, which is the trade the four curves in the figure are. That is not the same thing as buying reliability, and conflating the two would produce the advice “measure a longer stem when the answer is unclear”, which is right only if the uncertainty comes from the protractor.

What the pair costs, at a rise of 0.005Five seeded stems at each length, read at four protractor errors. With no reading error the pair needs 250 internodes — against the sixty the single parastichy number costs. At 0.25° per organ it needs 250; At 0.5° per organ it needs 400. The pattern's own scatter here is 0.70°, so the last of those is a reading error larger than the signal being read.0123451502504007601.1e+3internodes measured on one stemstems out of five returning the counted pairno reading error0.25° per organ0.5° per organrise 0.005 · disturbance 0.25 · pattern scatter 0.70°generated from a stated rule, not drawn to look right
Fig. 7 Two of the four curves on their own: no reading error, and half a degree per organ. Both step rather than creep, and the step moves right as the error grows. The gap between the two curves is what a better protractor is worth in internodes.

What the three tests cost separately

The readout has three clearance tests and they do not cost the same.

The main comb’s test is nearly free. On every stem where the pattern is a lattice at all, the main comb clears comfortably — 0.64 against a threshold of 0.19 at the working rise — and it is the test that fails only when there is no pattern.

The second comb’s test is what sets the length. It is the weaker signal and the threshold is the same, so it is the binding constraint at every length and every protractor error in the sweep.

The margin test costs the least in length and the most in refusals. It fails at one rise out of the five tried, and at that rise it refuses three runs of five — all three of which would have been wrong. So its price is paid in coverage rather than in stem: it makes one rung of the ladder unreadable rather than wrongly read.

That decomposition matters for anybody deciding whether to relax a test. Relaxing the second comb’s threshold buys shorter stems and immediately buys wrong answers, because the second comb’s score at short lengths is not small — it is uncertain, and an uncertain number that clears a lowered bar is a coin flip with a decimal point. Relaxing the margin test buys one more rung and buys the three wrong answers back with it.

The angles against the positions, rise by risefive rises, five seeded stems each. A filled mark is a run whose angle readout returned the pair the position counter finds in the same stem; an open mark is a refusal. At 0.032 the counter says 3/5 and the angles agree on 0 of 5, refusing 5. At 0.013 the counter says 5/8 and the angles agree on 5 of 5. At 0.01 the counter says 5/8 and the angles agree on 5 of 5. At 0.005 the counter says 8/13 and the angles agree on 5 of 5. At 0.008 the counter says 5/8 and the angles agree on 2 of 5, refusing 3. The two instruments share no code path: one is given a list of angles, the other a list of coordinates.risefive stems, read from the angles alonethe position counter0.032refusedrefusedrefusedrefusedrefused3 and 50.0135/85/85/85/85/85 and 80.015/85/85/85/85/85 and 80.0058/138/138/138/138/138 and 130.008refusedrefused5/8refused5/85 and 8seeded at 137.3°, 900 nodes per stemfilled where the two instruments agree
Fig. 8 The five rises, with the refusals visible. The coarse rise refuses because the second comb is not there; the transition rise refuses on three runs because no spacing wins by a band. Both refusals are the tests doing what they were built to do, and both are places a looser instrument would have reported.

What the price says about the instrument

Four times the length for the second number is a steep price and it is worth asking whether it is intrinsic.

Part of it is: the second comb is genuinely weaker, because the correlation reaches the second family through a longer chain or a weaker coupling, and no amount of cleverness makes a smaller signal larger. Part of it is the three clearance tests, which are deliberately conservative — the margin test alone turns three wrong answers into three refusals at one rise, and a version without it would report at shorter lengths and be wrong more often.

That trade is the one this site keeps making and it is worth naming as a choice rather than a fact. A readout that reported at 150 internodes with four right answers in five and one wrong would be cheaper and would look better in a table. What makes 250 the number quoted is that at 250 the wrong answers are gone, and a number that is sometimes wrong with no way of telling which is not a measurement.

The price beside the others

Set against the other prices this site has computed, the pair is expensive and not absurdly so.

A frequency claim about how often plants are Fibonacci needs tens of specimens. A junction measurement that distinguishes Murray’s law from Da Vinci’s needs one even fork or two thousand twigs. The noise-discrimination test needs sixty internodes. The pair needs two hundred and fifty internodes and photogrammetry.

What all four have in common is that the cost is dominated by one term and the term is different in each case: specimens, junction shape, sequence length, angular precision. A survey that budgeted for all four uniformly would overspend on three and underspend on one, which is the ordinary failure of a specification written without arithmetic behind it.

Shares its objects with

Essays that name at least two of the same things, and that neither author linked.

  • The test a plant could settle — both name autocorrelation, discrimination, divergence angle, identifiability, measurement, measurement error, sample size, specimen, summary statistic, survey
  • What a quiet plant is worth — both name autocorrelation, discrimination, divergence angle, honest limits, identifiability, measurement, measurement error, sample size, specimen, survey
  • What a refusal does not say — both name autocorrelation, discrimination, divergence angle, honest limits, identifiability, measurement, sample size, specimen, survey
  • The band decides the answer — both name discrimination, honest limits, identifiability, measurement, measurement error, residual, sample size, specimen
  • What one angle says about the next — both name autocorrelation, discrimination, divergence angle, ensemble, identifiability, measurement, measurement error, summary statistic
  • A window inside a rung — both name autocorrelation, divergence angle, honest limits, identifiability, measurement, parastichy pair, specimen

Named objects

A flat tag is an object no other essay names yet.

AutocorrelationCounting blindDiscriminationDivergence angleEnsembleHonest limitsIdentifiabilityMeasurementMeasurement errorParastichy pairResidualSample sizeSpecimenSummary statisticSurvey