What a plant might be doing

What a forgery has to know

A lattice with transported errors reproduces the comb and the pair, so one quantity is left: the two combs' relative strength. Weighted by distance the forgery puts more in the second comb than the first; the rule does the opposite. It matches only if the coupling is turned three to one towards the further neighbour, which no falloff supplies.

Worth reading first: Errors that pass between organs · The sequence has a memory · What a mechanism would have to show.

The previous essay left the comb reproduced by an arrangement with no rule in it, and the pair reproduced too, on every stem. That takes away the qualitative test. What is left is quantitative: the two combs a real stem shows are not equally strong, and the question is whether a forgery gets their proportions right as well as their positions.

It does not, unless it is tuned — and the tuning is in the wrong direction and by a large factor. This essay is that measurement, and it is the whole of what survives the previous phase’s claim.

The two combs, in the proportions the rule gives themThe ratio of the second comb to the main one, for a kinematic lattice whose errors are inherited from its two contact neighbours, against how unevenly that inheritance is split. The horizontal line is where the placement rule's own stems sit, at 0.65. Weighted by distance — the coupling a d⁻³ interaction would give, which at this rise favours the 13-neighbour by 1.26 to one because the 13-hop is the shorter — the forgery sits at 1.46, well above the rule. It reaches the rule's value only at about 3 to one the other way, which is a factor of 4 against what distance supplies and in the opposite direction.0.4000.6000.80011.201.40-0.30100.1760.3010.4770.699how much more strongly the error is inherited from the 8-neighbour than from the 13-neighbourthe second comb's strength as a fraction of the main comb'sthe placement rule: 0.65equal combs1:21:11.5:12:13:15:1at 3:1 the ratio is 0.75kinematic lattice · 3 seeds a pointgenerated from a stated rule, not drawn to look right
Fig. 1 The second comb’s strength as a fraction of the main comb’s, for a lattice whose errors are inherited from its two contact neighbours, against how unevenly that inheritance is split between them. The horizontal line is where the placement rule’s own stems sit. The forgery crosses it, and where it crosses is the point of the essay.

The quantity

The readout finds two combs. The main one sits at multiples of the smaller parastichy number; the second sits at the same spacing, offset by the difference of the pair. On the rule’s own stems at a rise of 0.005 the main comb averages 0.642 and the second 0.415, so the second is 0.65 of the first, and across five seeded stems the ratio runs 0.58 to 0.79.

Two combs, at a rise of 0.005The autocorrelation of 760 divergence angles from one stem held at a rise of 0.005. The filled teeth are the lags at multiples of 8; the open teeth are the second comb, at the same spacing offset by 5. Reading the spacing off the first and the offset off the second gives the pair 8 and 13, which is what the position counter reports for the same stem — from angles alone, with no coordinate anywhere in the calculation.-0.50000.500125810131621242629lag, in internodescorrelation between a divergence and the one that many internodes later816245132129spacing 8 · offset 5pair 8/13 — counter says 8/13sampling bandone stem · 760 divergences · disturbance 0.25generated from a stated rule, not drawn to look right
Fig. 2 The two combs on a stem the rule grew, which is where the ratio comes from. The filled teeth average 0.64 and the open teeth 0.42. Nothing in the previous phase asked why the first number is the larger — it was the main comb because it was the tallest, and that was the end of it.

That the main comb is the stronger looks like a definition rather than a measurement, because the readout calls the tallest comb the main one. It is not, and the reason it is not is the first surprise here: the readout finds the spacing first, and the spacing is the smaller parastichy number. Whether the comb at that spacing is stronger than the comb offset from it is then a fact about the stem.

The geometry says it should be the other way round

At a rise of 0.005 the surface distance from an organ to the one thirteen places before it is 0.0689 of a circumference, and to the one eight places before it is 0.0745. The thirteen-neighbour is the nearer of the two.

Which offsets give short hops, at a rise of 0.005The two lowest points are at 8 and 13, and those are the parastichy numbers. Offset 1 is high because a hop of one node is at least the rise, which is what makes a stem easier to count than a disc.00.2000.400102030index offsetmedian hop between node i and node i+m813300 nodes, 34 offsets triedshortest at 8 and 13
Fig. 3 The surface distance for each index offset at this rise, shortest first. Thirteen is shorter than eight — by eight per cent — which is what a lattice near a fork looks like and is entirely ordinary. Everything in this essay follows from the fact that the pair’s two members are not symmetric and the nearer of them is the larger number.

So a process that transmits error in proportion to how hard organs push each other should transmit more along the thirteen-hop than along the eight-hop. The repulsion in this site’s placement rule falls as the cube of distance, so the ratio of the two couplings would be (0.0745/0.0689)³ = 1.26 in favour of thirteen. Any falloff at all gives the same direction; the exponent only sets the size.

Give the forgery that weighting and the prediction comes out:

A lattice with an error inherited from the two contact neighboursThe autocorrelation of 759 divergence angles from a kinematic lattice at a divergence of 137.8261° and a rise of 0.005, with 0.5° of scatter on each azimuth. There is no placement rule anywhere in it: node i is put at exactly i times the divergence and then displaced. The only thing that differs between this figure and the control is the structure of the displacement — here, an error inherited from the two contact neighbours at coupling 0.7, 0.793:1 towards the eight. The largest comb mean is 0.439 against a sampling band of 0.073, and the readout returns 8/13.-0.50000.500125810131621242629lag, in internodescorrelation between a divergence and the one that many internodes later816245132129reads 8/13 · no rule in itmain 0.439 · band 0.073sampling bandkinematic lattice · 759 anglesgenerated from a stated rule, not drawn to look right
Fig. 4 The transported-error lattice with its coupling weighted by distance, at the ratio a d⁻³ interaction gives. It still returns the pair on every stem. But the second comb is now the taller of the two — 0.66 against 0.51 — which is the opposite of what a real stem does, and the readout’s labels are the wrong way round because the search names the spacing before it weighs the teeth.

The forgery’s ratio there is 1.30, against the rule’s 0.65: a factor of two, in the opposite direction, on the one quantity left.

Why the rule prefers the shorter index offset

This is the part that was not predicted and is reported as measured.

The rule places each organ at the minimum of a sum over the previous hundred or so, weighted by the cube of distance. Its correlations are not one-step transfers along two edges; they are the response of a whole neighbourhood, and the response has a structure that the distances alone do not give.

What can be said with confidence is the negative half: the rule’s comb ratio is not the ratio of its two couplings. If it were, the rule would show the same 1.26 lean towards thirteen that the distance-weighted forgery does, and it shows 0.65 the other way.

A candidate explanation, offered as a candidate: the readout’s main comb contains the harmonics — 8, 16, 24 — and a harmonic is a step taken twice. The correlation at 16 is what survives two eight-steps, so the main comb’s score mixes one-step and two-step transfers, while the second comb at 5, 13, 21 mixes one thirteen-step with an eight-plus-thirteen. If the rule’s transfer is efficient at short chains and lossy at long ones, the comb whose members are reachable by fewer steps wins, and that is the eight-comb whatever the distances say. That would make the ratio a measure of how quickly a neighbourhood’s response decays with chain length, which is a property of the interaction range rather than of the geometry.

It is a candidate because nothing here separates it from two other stories, and naming a mechanism this site has not tested would be exactly the move the site exists to refuse.

The two other stories, so that the candidate can be compared with something. One: the rule’s response is not a transfer at all but a relaxation — a displaced organ changes the energy landscape the next few see, and the neighbourhood re-settles — in which case the comb weights are set by how the landscape’s curvature divides between the two directions, and the distances enter only through that. Two: the eight-chain and the thirteen-chain differ in how many organs lie between their endpoints in production order, so a disturbance travelling along the thirteen-chain has more chances to be overwritten by fresher noise, and the ratio measures a competition between transfer and refreshment rather than a property of either chain.

All three predict the observed sign. None of them predicts the observed size without a calculation nobody here has done, and the difference between a candidate explanation and a result is exactly that calculation.

A stem gathers neighbours linearly; a growing disc barely gathers them at allOn a cylinder of circumference 1 with a rise of 0.005, the nodes within distance d number 2d/0.005 once d exceeds one turn — a fitted exponent of 1.011 and 400 per unit against the 400 the geometry fixes. In the disc model an element of age k sits at radius e^(0.4k), so each doubling of the distance adds the same two or three neighbours rather than twice as many.01234-0.50000.50011.50distance from the node, log₁₀neighbours, log₁₀a stemslope 1a disca logarithmrise 0.005 · 24000 nodes · meristem growth 0.4slope 1.011 against slope 1
Fig. 5 How many organs sit within a given distance of the one being placed, at this rise — the neighbourhood the rule actually sums over. It contains far more than two organs, which is why the rule’s correlation structure is not a two-edge transport and why the comb ratio it produces is not the ratio of two couplings.

What the tuned forgery can do

Turn the coupling ratio the other way — make the forgery inherit more from the eight-neighbour than from the thirteen-neighbour, against what the distances say — and the ratio walks down through the rule’s value.

At 2:1 towards the eight it is 0.97. At 3:1 it is 0.75. At 5:1 it is 0.46. So somewhere around 3:1 the forgery sits on the rule, and it sits on more than the ratio: main comb 0.601 against the rule’s 0.642, second 0.453 against 0.415, recorded scatter 0.82° against 0.70°.

A lattice with an error inherited from the two contact neighboursThe autocorrelation of 759 divergence angles from a kinematic lattice at a divergence of 137.8261° and a rise of 0.005, with 0.5° of scatter on each azimuth. There is no placement rule anywhere in it: node i is put at exactly i times the divergence and then displaced. The only thing that differs between this figure and the control is the structure of the displacement — here, an error inherited from the two contact neighbours at coupling 0.75, 3:1 towards the eight. The largest comb mean is 0.610 against a sampling band of 0.073, and the readout returns 8/13.-0.50000.500125810131621242629lag, in internodescorrelation between a divergence and the one that many internodes later816245132129reads 8/13 · no rule in itmain 0.610 · band 0.073sampling bandkinematic lattice · 759 anglesgenerated from a stated rule, not drawn to look right
Fig. 6 The tuned forgery. Every quantity this site can read off an angle sequence agrees with a stem the rule grew: the pair, the spacing, the offset, both comb strengths and the scatter. There is no placement rule in it, no minimum is taken anywhere, and no organ influences where any other organ goes.
Transported errors report the same pair every timeeight kinematic lattices, differing only in the seed of their disturbance, each read by the same instrument. The disturbance at each node is inherited from the nodes 8 and 13 places back, at a coupling of 0.75. Every stem returns 8/13, which is the pair the positions give and the pair the placement rule's own stems give. There is no placement rule in any of these arrangements.stemwhat the angles say18/13the lattice's own pair28/13the lattice's own pair38/13the lattice's own pair48/13the lattice's own pair58/13the lattice's own pair68/13the lattice's own pair78/13the lattice's own pair88/13the lattice's own pairthe positions say 8/13kinematic lattice · inherited errorgenerated from a stated rule, not drawn to look right
Fig. 7 And it reports the same pair on every stem, which is the test that caught the periodic forgery. This one passes it.

So the honest summary is a conditional, and the condition is about a free parameter rather than about a measurement.

If the transport is distance-weighted, the comb ratio separates it from the rule — 1.30 against 0.65, a separation of a factor of two on a quantity that five stems measure to about ±0.1.

If the coupling ratio is free, nothing does. A forger allowed to pick how much each neighbour contributes has two knobs and is being asked to match two numbers, and two knobs match two numbers.

Which of those a plant is

This is where the essay stops being about arithmetic, and it is worth stating what would settle it rather than pretending it is settled.

A coupling three to one in favour of the further neighbour is not something a falloff produces. Every interaction that decreases with distance gives the nearer neighbour the larger share, so the tuned forgery needs its transport to be stronger where the organs are further apart — a factor of four against what distance supplies, and in the opposite direction.

There are ways that could be true. The eight-chain and the thirteen-chain are different tissue: one runs up the steeper spiral and one the shallower, and if transport happens along vascular strands rather than through contact then the strands’ geometry is not the organs’ geometry. But that is a hypothesis with its own predictions, not a free parameter, and it would be testable — which is the shape this thread keeps arriving at.

So the measurement’s value is that it converts a qualitative claim into a quantitative one with a stated escape. Before this essay: a comb shows the plant computes its pattern, which is false. After it: a comb ratio below one is inconsistent with error transport weighted by distance, and consistent with the placement rule, which is true, and which a real plant could be measured against.

Which arrangements carry a comb, and what each one reportsThe largest comb mean in five arrangements at a rise of 0.005, all read by the same instrument at the same length, with the sampling band of 0.073 marked. Only the first is a placement rule; the other four are kinematic lattices with no rule in them, differing from one another only in how their azimuth errors are structured. Independent errors and errors with a memory leave nothing to read. A repeating error puts up a comb and names a partner that is not the lattice's. Errors inherited from the contact neighbours reproduce both the comb and the pair.three sampling bandsthe placement rule0.6428/13independent errors0.031refusedan error with a memory0.014refusedan error that repeats0.4338/10, 8/12errors passed between neighbours0.5538/13one rule, four kinematic latticesgenerated from a stated rule, not drawn to look right
Fig. 8 The five arrangements this thread compares, on comb strength alone — the quantity that no longer separates them. What separates them is one row down from this chart: not how tall the main comb is, but how tall the second is relative to it.

Three things the ratio is not

A quantity that survives when the qualitative test has failed attracts more weight than it can carry, so it is worth naming what this one does not do.

It is not a test of the placement rule against everything. It compares one model of error transport — inheritance along the two contact chains, with a coupling split — against the rule. A plant could be doing something that is neither, and the ratio would report whichever of the two it happened to resemble. The list of rivals this thread has tested is now three long, and the list of rivals that exist is not.

It is not independent of the rung. The ratio 0.65 was measured at a rise of 0.005, where the pair is 8/13 and the thirteen-hop is the shorter by eight per cent. At a coarser rise the same asymmetry has a different size and sometimes a different sign, so the number a plant should be compared against depends on which rung it is on — which means the comparison needs the rise, which needs the internode length and the organ size, which is two more measurements on the specimen.

Two combs, at a rise of 0.013The autocorrelation of 760 divergence angles from one stem held at a rise of 0.013. The filled teeth are the lags at multiples of 5; the open teeth are the second comb, at the same spacing offset by 3. Reading the spacing off the first and the offset off the second gives the pair 5 and 8, which is what the position counter reports for the same stem — from angles alone, with no coordinate anywhere in the calculation.-0.50000.500125810131621242629lag, in internodescorrelation between a divergence and the one that many internodes later510152025303813182328spacing 5 · offset 3pair 5/8 — counter says 5/8sampling bandone stem · 760 divergences · disturbance 0.3generated from a stated rule, not drawn to look right
Fig. 9 The same two combs one rung coarser, where the pair is 5 and 8. The ratio here is not the ratio above, and a survey quoting a single number for “the rule’s comb ratio” would be quoting a number that belongs to one rise.

And it is not a measurement anybody has made. No published work reports the autocorrelation of a divergence sequence at all, let alone the relative heights of two residue classes in it. The quantity is available from data that has been collected for two centuries — a list of divergence angles down a stem — and has not been looked at, because until the previous phase nobody had a reason to look at lags rather than at the mean.

What the previous phase should have said

With the measurement in hand it is possible to write the sentence the previous phase was reaching for, and the difference between the two is instructive.

What it said: the comb is the first quantity here that separates a process from a form.

What it could have said: the comb separates an arrangement whose errors are independent from one whose errors are transmitted along its contact graph, and the ratio of the two combs constrains how that transmission is weighted.

The second sentence is longer, weaker, and true. It also has a property the first does not: it names the alternative it excludes, so a reader can ask whether a plant might be the alternative. The first sentence excludes “a plant that merely has a pattern”, which is not a model of anything and therefore not something a measurement can rule out.

That is the general form of the lesson, and this site has recorded it twice before under other names — a claim that survives is one whose contrary is something a plant could be.

What it would cost to measure on a plant

The ratio is a ratio of two quantities that both need the pair to be readable, so it inherits the pair’s cost: two hundred and fifty internodes, a reading error under a quarter of a degree, a shoot slower than about two hundred and fifty nodes to the rung. It does not obviously need more than that, because the ratio is more forgiving than either comb — a common error in both numerators divides out.

What it does need, and what the previous requirements did not, is more than one specimen at the same rung. The ratio varies from 0.58 to 0.79 across five stems grown from the same rule with different disturbance seeds, which is a spread of a third, and separating 0.65 from 1.30 with a spread of a third takes a handful of plants rather than one.

The protocol, written out, is four steps and none of them is new machinery.

One. Record the divergence angle at every internode down two hundred and fifty internodes of a single shoot, to a quarter of a degree, on each of half a dozen plants of the same species at the same stage.

Two. On each plant, run the two-comb readout. Discard the plants it refuses, and record how many it refused — a refusal rate is a measurement of the sample, not a nuisance.

Three. Check that the reported pairs agree with each other and with a parastichy count made on the same shoots. Disagreement here is the periodic forgery’s signature and the reading stops if it appears.

Four. Take the ratio of the second comb’s mean to the main comb’s, on each plant, and compare the set against 0.65 and against 1.30. With a per-plant spread of about a third, six plants separate those two hypotheses at a comfortable margin and two do not.

The fourth step is the only one this essay adds, and it costs nothing extra in fieldwork — the two numbers are already computed by the readout that produced the pair. What it costs is the specimens, because the spread across stems is not small, and the reason the spread is not small is that a comb strength is a mean over three or four teeth of a correlation estimated from a few hundred numbers.

The memory of a divergence sequence, at 0.75° of scatterWith no noise at all the lag-one correlation is 0.54: the rule corrects itself, so a lattice arrives with a memory in it. Matched at the same recorded scatter, placement noise leaves -0.09, jostle noise leaves 0.67, field noise leaves 0.51. The band is ±0.13, which is what an uncorrelated sequence of this length gives.-0.25000.2500.500123456lag, in nodescorrelation between a divergence and the one that many nodes laterno noiseplacement noisejostle noisefield noisesampling band5 runs each · 243 divergences per runmatched at 0.75° of scatter
Fig. 10 The other statistic this site reads off an angle sequence, for comparison of cost. Lag one needs sixty internodes and one plant; the pair needs two hundred and fifty; the ratio needs two hundred and fifty on several plants. Each step up in what the measurement can distinguish has cost about a factor of five in stem, which is a pattern worth noticing before proposing the next one.
Two shapes, two ranges, one contrastThe exponential's lattice ends at 3.63 spacings and the gaussian's at 2.25 — ranges 47% apart — and at those two ranges the contrast is 5.74 and 6.09, 6% apart. The band is what the exponent route leaves: 3.98 at p = 1, where the uncut rule makes nothing, and 7.63 at p = 1.25, where it makes a lattice.204012345range at which the interaction has halved, in local spacingsnear-shell contrast — the first shell's variation over the second'swhat the exponent sweep leavesexponential ends here — 5.74gaussian ends here — 6.09p = 1 · shells 0–2 and 2–4 spacingscontrasts 6% apart, ranges 47%
Fig. 11 A precedent from the interaction-range thread, which found the same shape of answer: the quantity that survives a change of model is not the one everybody quotes but a ratio built out of it. That thread’s invariant was a contrast; this one’s is a ratio of two combs. Both are cases of a raw number being model-dependent and a normalised one not being.
Every family but two is the sum of two othersFour heads and the contact families each actually has. An arc arrives at every family that is the sum of two smaller ones; the two with no arc arriving are the generators, and on every head they are the two smallest. whorled, 144°: 2, 3, 5 — golden, 137.508°: 8, 13, 21, 34, 55, 89 — Lucas, 99.502°: 11, 18, 29, 47, 76 — rational, 137.5°: 8, 13, 21, 34, 55, 89 — 137.0°: 8, 13, 21, 29, 50, 71, 92, 113. So once a pair is counted the rest is arithmetic, and a third counted family is a prediction rather than a second measurement.whorled, 144°from 2 and 3+2235golden, 137.508°from 8 and 13+8+13+21+3481321345589Lucas, 99.502°from 11 and 18+11+18+291118294776rational, 137.5°from 8 and 13+8+13+21+3481321345589137.0°from 8 and 13+8+8+21+21+21+218132129507192113contact families above 2% of all cell contactsfilled dots are the two that are not sums
Fig. 12 And the arithmetic underneath all of it. The second comb exists because the lattice’s offsets are generated by two numbers, so a disturbance travelling along contacts reaches 21 as 8 plus 13. Everything in this essay is about the relative weight of the two generators, which is the only freedom the arithmetic leaves.

What links here

Computed from the collection, not written here: the essays that point at this one.

Shares its objects with

Essays that name at least two of the same things, and that neither author linked.

  • A disturbance with a memory — both name autocorrelation, discrimination, evidence, honest limits, measurement, noise, null model, parastichy pair, the placement rule
  • A periodicity is not a lattice — both name autocorrelation, discrimination, evidence, identifiability, lattice offset, measurement, noise, null model, parastichy pair
  • The control a survey would need — both name autocorrelation, discrimination, evidence, honest limits, identifiability, measurement, null model, parastichy pair, transport
  • What a quiet plant is worth — both name autocorrelation, discrimination, evidence, honest limits, identifiability, measurement, noise
  • What a refusal does not say — both name autocorrelation, discrimination, evidence, honest limits, identifiability, measurement, noise
  • A refusal with a reason — both name autocorrelation, discrimination, honest limits, identifiability, measurement, parastichy pair

Named objects

A flat tag is an object no other essay names yet.

AutocorrelationDiscriminationEvidenceHonest limitsIdentifiabilityLattice offsetMeasurementNearest neighbourNoiseNull modelOne parameterParastichy pairThe placement ruleRepulsionTransport